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adell [148]
3 years ago
10

How many milliliters of a 5.0 M H2SO4 stock solution would you need to prepare 101.5 mL of 0.17 M H2SO4?

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
6 0

Answer:

3.451 mL.

Explanation:

  • It is a dilution process.
  • We have the rule states that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.

<em>(MV) before dilution = (MV) after dilution</em>

M before dilution = 5.0 M.

V before dilution = ??? mL.

M after dilution = 0.17 M.

V after dilution = 101.5 mL.

∴ The volume before dilution = (MV) after dilution / M before dilution = (0.17 M)(101.5 mL) / (5.0 M) = 3.451 mL.

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Just find Ag and F on periodic table, find g/mol for each one and add them together
3 0
3 years ago
Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
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<u>Given:</u>

Calculated density values-

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Sample volume = 2.1 cm3

<u>To determine:</u>

The identity of the unknown sample

<u>Explanation:</u>

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5 0
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Calculate the volume of a 1.25 M solution of HCN made from 31 grams of HCN
fenix001 [56]

Answer:

V HCNsln = 0.9176 L

Explanation:

V HCNsln = ?

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5 0
2 years ago
5) answer is A
Burka [1]

Answer:

A)  positive; added

Explanation:

Based on the reaction:

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<em>2 moles of NaHCO3 requires 129kJ to produce 1 mole of Na2CO3, 1 mole of H2 and 1 mole of CO2.</em>

<em />

That means, the energy must be added being, thus, an exothermic reaction. The exothermic reactions have ΔH >0.

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3 0
2 years ago
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