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sasho [114]
3 years ago
15

you arrive in hampton 45 seconds after you left York college which is 50 feet away how fast did you travel

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
4 0
.9 feet per second, because 45 divided by 50 equals .9
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Determine the amount of both hydrogen and oxygen in a 500mL sample of Water.
alina1380 [7]
There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.
3 0
3 years ago
(b) Which of the following is a mixture?
bija089 [108]

Answer:

a

Explanation:

Mixture is a combination of two or more elements and sodium is an element with a chemical symbol Na and a charge of +1 and chloride too is an element with a chemical symbol Cl and a charge of -1 so when these two elements are combine it form a chemical solution called Sodium chloride

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2 years ago
The free energy for the oxidation of glucose to CO2 and water is -686 kcal/mol, and the free energy for the reduction of NAD+ to
vitfil [10]

Answer:

Most of free energy available from oxidation of the glucose remains in pyruvate.

Explanation:

The overall reaction of the process glycolysis is:

Glucose + 2 NAD⁺ + 2 ADP + 2 Pi ⇒ 2 Pyruvate + 2 NADH + 2 H⁺ + 2ATP

Glucose is oxidized to give 2 molecules of pyruvate and 2 molecules of NADH and ATP (Energy currency).

<u>Though the free energy of oxidation of glucose is high but only 2 NADH is formed because the most of the free energy that is being released from the oxidation of glucose remains in the pyruvate which is produced in the reaction and thus only 2 molecules are formed.</u>

6 0
3 years ago
What is meant by atomic number?
SpyIntel [72]
C I hope I help good luck
8 0
2 years ago
Determine the partial pressure and number of moles of each gas in a 15.75-L vessel at 30.0 C containing a mixture of xenon and n
lawyer [7]

Answer:

The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981

Explanation:

Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761

As we know,

\chi_{Ne} + \chi_{Xe} = 1\\\chi_{Ne}= 1- 0.761\\\chi_{Ne}= 0.239

According to Dalton's Law of partial pressure-

P_i=\chi_i\times P_{total}

Where,

P_i=The pressure of the gas component in the mixture

\chi_i= Mole fraction of that gas component

P_t= The total pressure of the mixture

P_{Xe}=(0.761)\times(6.5)\\P_{Xe}= 4.95 atm\\\\\\P_{Ne}=(0.239)\imes (6.5)\\P_{Ne}= 1.55 atm

<u>Calculation: </u>

To calculate the number of moles,

PV=nRT

n=\frac{PV}{RT}

n_{Xe}= \frac{4.95\times 15.75}{0.0821\times303 }\\ n_{Xe}= \frac{77.96}{24.87} \\n_{Xe}= 3.13\,mole \\\\\\n_{Ne}= \frac{1.55\times 15.75}{0.0821\times303 }\\\\n_{Ne}=\frac{24.41}{24.87}\\ n_{Ne}=0.981 \,mole

Learn more about Dalton's Law of partial pressure here;

brainly.com/question/14119417

#SPJ4

4 0
1 year ago
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