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3 years ago

you arrive in hampton 45 seconds after you left York college which is 50 feet away how fast did you travel

Chemistry

1 answer:

Nimfa-mama [501]3 years ago

4 0

.9 feet per second, because 45 divided by 50 equals .9

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Why do we have to pay if its just learning

Oxana [17]

Answer:

what are we paying for?

Explanation:

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4 years ago

Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?

german

Answer : The correct option is, (A) $AlCl_3$

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) $AlCl_3$

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of $AlCl_3$ will be,

$AlCl_3\rightarrow Al^{3+}+3Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Al^{3+}+3Cl^{-}$ = 1 + 3 = 4

(B) $KI$

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of $KI$ will be,

$KI\rightarrow K^{+}+I^{-}$

So, Van't Hoff factor = Number of solute particles = $K^{+}+I^{-}$ = 1 + 1 = 2

(C) $CaCl_2$

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of $CaCl_2$ will be,

$CaCl_2\rightarrow Ca^{2+}+2Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Ca^{2+}+2Cl^{-}$ = 1 + 2 = 3

(D) $MgSO_4$

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of $MgSO_4$ will be,

$MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}$

So, Van't Hoff factor = Number of solute particles = $Mg^{2+}+SO_4^{2-}$ = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, $AlCl_3$

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3 years ago

What happens to ice as it warms up

son4ous [18]

Ice starts to melt and turns into water as it melts

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3 years ago

Read 2 more answers

When a warm air mass and a cold air masses meet but they push at each other and neither one can move (at a stand off) it’s calle

Tom [10]

This is called a Cold Front.

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3 years ago

the burning of wood is a chemical reaction between cellulose molecules in the wood and oxygen the products are carbon dioxide an

Sati [7]

Put the wood and excess oxygen in a closed container that contains some device that can create a spark (to start the reaction).

Determine the mass of container + contents.

Start the reaction and, after everything has cooled down, again determine the mass of container + contents.

If the two masses are the same, you have demonstrated that the reaction obeys the Law of Conservation of Mass.

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3 years ago