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Elodia [21]
2 years ago
11

A force acts on a body of mass 13 kg initially at restThe force acts for 10 seconds, and once it quits, the body covers 60 m in

the next 6 seconds . Find the force that acted on the body
Physics
2 answers:
Ghella [55]2 years ago
6 0

Answer:

uguuffuufufufufucucucuvuvhvuchcyctxxtrxtccyyvuvubjbubbu

elixir [45]2 years ago
3 0

Answer: 13 N

Explanation: You have to use F=m * g

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Which of the following statements are true? Positively charged objects attract other positively charged objects. Negatively char
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The statement that is true is that positively charged objects attract negatively charged objects. This is due to a law that states 'like forces attract while unlike forces repel. This same concept applies to magnetism. If you put two similar poles together, for example; if you place two south poles together. You feel a separating force between the two poles. But if you place two opposite poles together they attract each other. Hope i helped. <span />
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A device that converts mechanical energy into electricity is a
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Answer:

An electric generator is a device that converts a form of energy into electricity.

Explanation:

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For a movie stunt, an empty truck with a mass of 2000 kg goes 10 m/s and runs into a stopped car of mass 1000 kg. the truck then
babunello [35]

ANSWER

Both trucks will move together with speed v = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

EXPLANATION

As we know that there is no external force on the system of two trucks

So here momentum of the two trucks before collision and after collision will remain same

So here we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

so here we will have

v_{1i} = 10 m/s

v_{2i} = 0

m_1 = 2000 kg

m_2 = 1000 kg

now we will have

2000\times 10 + 1000\times 0 = (2000 + 1000) v

v = \frac{20000}{3000} = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

3 0
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Unpolarizedlight of intensity I_0 is incident on three polarizingfilters. The axis of the first is vertical, that of the secondi
Marina86 [1]

To solve this problem it is necessary to apply the concepts related to the law of Malus which describe the intensity of light passing through a polarizer. Mathematically this law can be described as:

I = I_0 cos^2\theta

Where,

I_0 = Indicates the intensity of the light before passing through the polarizer

I = Resulting intensity

\theta= Indicates the angle between the axis of the analyzer and the polarization axis of the incident light

From the law of Malus when the light passes at a vertical angle through the first polarizer its intensity is reduced by half therefore

I_1= \frac{I_0}{2}

In the case of the second polarizer the angle is directly 60 degrees therefore

I_2 = I_1 cos^2\theta

I_2 = (\frac{I_0}{2} ) cos^2(60)

I_2 = 0.125I_0

In the case of the third polarizer, the angle is reflected on the perpendicular, therefore, its angle of index would be

\theta_3 = 90-60 = 30

Then,

I_3 = I_2 cos^2\theta_3

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I_3 = 0.09375I_0

Then the intensity at the end of the polarized lenses will be equivalent to 0.09375 of the initial intensity.

5 0
2 years ago
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