A starship is circling a distant planet of radius R. The astronauts find that the free-fall acceleration at their altitude is ha
1 answer:
Answer:
h = R/4 = 1.5925 x 10⁶ m = 1592.5 km
Explanation:
The variation in the value of acceleration due to gravity value with respect to the altitude is given by the following general formula:
where,
h = altitude from surface of earth = ?
g = acceleration due to gravity on surface of earth = 9.81 m/s²
R = Radius of Earth = 6.37 x 10⁶ m
g' = acceleration due to gravity at given altitude = g/2
Therefore,
<u>h = R/4 = 1.5925 x 10⁶ m = 1592.5 km</u>
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Answer:
665 ft
Explanation:
Let d be the distance from the person to the monument. Note that d is perpendicular to the monument and would make 2 triangles with the monuments, 1 up and 1 down.
The side length of the up right-triangle knowing the other side is d and the angle of elevation is 13 degrees is
Similarly, the side length of the down right-triangle knowing the other side is d and the angle of depression is 4 degrees
Since the 2 sides length above make up the 200 foot monument, their total length is
0.231d + 0.07d = 200
0.301 d = 200
d = 200 / 0.301 = 665 ft
Assuming you are looking for the acceleration a:
1.
2.
where T is the tension and a is the acceleration of the blocks. The acceleration of the two blocks and the acceleration of the pulley must be equal.
The torque on the pulley is given by:
3.
where
and 
.
Combining the three equations:
1.
2.
where T is the tension and a is the acceleration of the blocks. The acceleration of the two blocks and the acceleration of the pulley must be equal.
The torque on the pulley is given by:
3.
where
Combining the three equations: