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Eva8 [605]
2 years ago
15

A starship is circling a distant planet of radius R. The astronauts find that the free-fall acceleration at their altitude is ha

lf the value at the planet's surface. How far above the surface are they orbiting?
Physics
1 answer:
Bezzdna [24]2 years ago
6 0

Answer:

h = R/4 = 1.5925 x 10⁶ m = 1592.5 km

Explanation:

The variation in the value of acceleration due to gravity value with respect to the altitude is given by the following general formula:

g' = g(1-2\frac{h}{R})

where,

h = altitude from surface of earth = ?

g = acceleration due to gravity on surface of earth = 9.81 m/s²

R = Radius of Earth = 6.37 x 10⁶ m

g' = acceleration due to gravity at given altitude = g/2

Therefore,

\frac{g}{2}  = g(1-2\frac{h}{R})\\\\2\frac{h}{R} = 1-\frac{1}{2}\\\\2\frac{h}{R} = \frac{1}{2}\\\\\frac{h}{R} = \frac{1}{4}\\\\

<u>h = R/4 = 1.5925 x 10⁶ m = 1592.5 km</u>

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Explanation:

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The maximum work is done when the force is parallel to the distance direction.

The minimum work is done when the force is at an angle of 90° to the distance direction.

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2 years ago
A spring is 20cm long is stretched to 25cm by a load of 50N. What will be its length when stretched by 100N. assuming that the e
IgorLugansk [536]

Answer:

Final Length = 30 cm

Explanation:

The relationship between the force applied on a string and its stretching length, within the elastic limit, is given by Hooke's Law:

F = kΔx

where,

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Δx = change in length of spring

First, we find the spring constant of the spring. For this purpose, we have the following data:

F = 50 N

Δx = change in length = 25 cm  - 20 cm = 5 cm = 0.05 m

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50 N = k(0.05 m)

k = 50 N/0.05 m

k = 1000 N/m

Now, we find the change in its length for F = 100 N:

100 N = (1000 N/m)Δx

Δx = (100 N)/(1000 N/m)

Δx = 0.1 m = 10 cm

but,

Δx = Final Length - Initial Length

10 cm = Final Length - 20 cm

Final Length = 10 cm + 20 cm

<u>Final Length = 30 cm</u>

6 0
3 years ago
a small table has a mass of 4kg, stands on four legs, each leg having an area of 0.001 m2. what is the pressure exerted by the t
Gemiola [76]

Answer:

P = 10 kPa

Explanation:

Given that,

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Choose the law each sentence describes. This law relates a planet's orbital period and its average distance to the Sun. The orbi
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These are the Kepler's laws of planetary motion.

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Explain how the potential energy of two charged particles depends on the distance between the charged particles and on the magni
maks197457 [2]

Answer:

According to Coulomb's Law, the potential energy of two charged particles is directly proportional to the product of the two charges and inversely proportional to the distance between the charges

Explanation:

According to Coulomb's Law, the potential energy of two charged particles is directly proportional to the product of the two charges and inversely proportional to the distance between the charges.  Since the potential energy  of two charged particles is directly proportional to the product of the two charges, its magnitude increases as the charges of the particles increases. For like charges, the potential energy is positive(the product of the two alike charges must be positive) and since potential energy is inversely proportional to the distance between the charges therefore it decreases as the particles get farther apart . For opposite charges, the potential energy is negative(the product of the two opposite charges must be negative) and since potential energy is inversely proportional to the distance between the two charges, it becomes more negative as the particles get closer together.

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3 years ago
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