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Eva8 [605]
2 years ago
15

A starship is circling a distant planet of radius R. The astronauts find that the free-fall acceleration at their altitude is ha

lf the value at the planet's surface. How far above the surface are they orbiting?
Physics
1 answer:
Bezzdna [24]2 years ago
6 0

Answer:

h = R/4 = 1.5925 x 10⁶ m = 1592.5 km

Explanation:

The variation in the value of acceleration due to gravity value with respect to the altitude is given by the following general formula:

g' = g(1-2\frac{h}{R})

where,

h = altitude from surface of earth = ?

g = acceleration due to gravity on surface of earth = 9.81 m/s²

R = Radius of Earth = 6.37 x 10⁶ m

g' = acceleration due to gravity at given altitude = g/2

Therefore,

\frac{g}{2}  = g(1-2\frac{h}{R})\\\\2\frac{h}{R} = 1-\frac{1}{2}\\\\2\frac{h}{R} = \frac{1}{2}\\\\\frac{h}{R} = \frac{1}{4}\\\\

<u>h = R/4 = 1.5925 x 10⁶ m = 1592.5 km</u>

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Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
3 years ago
Of the following the only process not involed in the making of clastic rocks is:
Elden [556K]
The answer is B. build up of plant materials. This is because those rocks that are composed of materials, which are organic matters from decaying plants, formed by biological activity are called biogenic or organic or non-clastic rocks. On the other hand, clastic rocks are made up of gravel, sand, silt, and clay.
6 0
3 years ago
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A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i
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Answer:

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

v^2=u^2+2as

0^2=14.5^2+2\times a\times 18.25

a=-5.76m/sec^2

We know that acceleration is given by

a=\mu g

5.76=\mu\times  9.81

\mu =0.587

So coefficient of friction will be 0.587

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3 years ago
The sum of all forces acting on an object
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Answer:

The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

Explanation:

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4 0
3 years ago
A 6 m/s vector pointing North is added to a 2 m/s vector pointing East. What are the magnitude and direction of the resultant?
irina [24]

Answer:

A + B = C      Ax = 2   Ay = 0    Bx = 0  By = 6

Ax + Bx = Cx = 2

Ay + By = Cy = 6

C = (2^2 + 6^2)^1/2 = 6.32

Tan Cy / Cx = 6 / 2 = 3

Cy at 71.6 deg

6 0
3 years ago
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