The moles of disodium edta used is calculated using the below formula
moles =molarity x volume in liters
molarity=0.050m
volume in liters = 22/1000=0.022 L
moles is therefore= 0.022 x0.050 =1.1 x10^-3 moles of disodium edta
Arrhenius model considers a base a compound that produces OH(-)
H2SO4 produces H(+) and is an acid
C6H12O6 is an organic product, sugar, that does not produce OH(-)
HOClO2 = HClO3, which produces H(+) and is an acid
NH3 is believed to ionize in water and produce NH4(+) and OH(-).
As per this the answer is NH3.
Nevertheless, NH3 is not a good example of bases as per Arrhenius model, because it is not so evident that NH3 produces OH(-).
Answer:
Explanation:
how many grams and moles of gold are present in 8.09 x 10^28 atoms of gold?
there are 6.02 x 10^23 molecules or atoms in 1 mole
of a compound or element
8.09 x 10^28 /(6.02 x 10^23) = 1.34 x 10^5 moles of Au
1 mole of gold (see periodic table for #79) 197 g
so 1.34 x 10^5 moles of Au weigh
197 x 1.34 x 10^5 = 2.64 x 10^7 g
your little gold treasure is worth
Gold Price Per Gram $59.87 x 2.64 x 10^7=
$$$$ 1.58 x 10^9
=$ 1,580,000,000
P= 1.50 atm
V= 3 L
R= 0.08205<span> L∙atm/mol∙K
T= 300 K
n= ?
we all this information, we can tell that we need to use ideal gas formula
PV= nRT
if we rearrange the formula for n, we get--> n= PV/ RT
let's plug in the values.
n= 1.5 x 3/ (0.08205 x 300)= 0.18 moles
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velocity is speed and direction so it should be expressed in mph f/s (feet per second) with a direction like North, right, left,
ex) 5mph south