At constant temperature a bicycle tire pump contains 252mL of air at 995kPa pressure. The plunger of the pump is pushed down unt
2 answers:
Answer:
Explanation:
Hello,
In this case, we notice a relationship between the volume and pressure of a gas, accounting for the Boyle's law which has the following form:
In this case, we asked to find the pressure after the pump is pushed down, it means as shown below:
Such pressure increase accounts for a compression process at which the volume is decreased at the same time.
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Answer:
311.25k
Explanation:
The question assumes heat is not lost to the surroundings, therefore
heat emitted from hotter sample ( )= heat absorbed by the less hotter sample(
)
The relationship between heat (q), mass (m) and temperature (t) is
where c is specific heat capacity, temperature change.
=
equating both heat emitted and absorb
where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.
C will cancel out since both are water and they have the same specific heat capacity.
so we have
where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?
-50 * ( - 330) = 30 * (
- 280)
-50 + 16500 = 30
- 8400
80 = 16500+8400
80 = 24900
= 24900/80 = 311.25k