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oee [108]
2 years ago
7

The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =

200(1 – 0.956e–0.18t ) where L(t) is the length (in centimeters) of a fish t years old.
(a) Find the rate of change of the length as a function of time
Physics
1 answer:
Ann [662]2 years ago
8 0

Answer:

Rate of change of length as a function of time is given by \frac{dL(t)}{dt}=34.416e^{-0.18t}

Explanation:

The length as function of time is given byL(t)=200(1-0.956e^{-0.18t})

Differentiating with respect to time we get

\frac{dL(t)}{dt}=\frac{d(200(1-0.956e^{-0.18t}))}{dt}\\\\\frac{dL(t)}{dt}=200\frac{d(1-0.956e^{-0.18t})}{dt}\\\\=200\times 0.18\times 0.956e^{-0.18t}\\\\\frac{dL(t)}{dt}=34.416e^{-0.18t}

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Answer:

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