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3 years ago

How does the media restrict what is discussed in the pubic sphere

1 answer:

4 0

Public sphere is a concept created in the 18th century and further developed by Jürgen Habermas, who stated that the public sphere was characterized by it's critical nature in contraposition to the representative nature of the feudal system

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The starter motor of a car engine draws a current of 140 A from the battery. The copper wire to the motor is 4.20 mm in diameter

GenaCL600 [577]

Answer:

(a)106.4C

b)0.5676mm

Explanation:

(a)To get the charge that have passed through the starter then The current will be multiplied by the duration

I= current

t= time taken

Q= required charge

Q= I*t = 140*0.760 = 106.C

(b) b. How far does an electron travel along the wire while the starter motor is on?(mm)

diameter of the conductor is 4.20 mm

But Radius= diameter/2= 4.20/2=

The radius of the conductor is 2.1mm, then if we convert to metre for consistency same then

radius of the conductor is 0.0021m.

We can now calculate the area of the conductor which is

A = π*r^2

= π*(0.0021)^2 = 13.85*10^-6 m^2

We can proceed to calculate the current density below

J = 140/13.85*10^-6 = 10108303A/m

According to the listed reference:

Where e= 1.6*10^-19

n= 8.46*10^28

Vd = J/(n*e) = 10108303/ ( 8.46*10^28 * 1.6*10^-19 ) =0.0007468m/s=0 .7468 mm/s

Therefore , the distance traveled is:

x = v*t = 0.7468 * 0.760 = 0.5676mm

7 0

2 years ago

Air at 200 kpa and 800k enters an adiabatic nozzle at low velocity (can be considered negligible) and is discharged at a pressur

scZoUnD [109]

the answer is c. the actual exit temperature

7 0

3 years ago

A ball is thrown up in the air. When it falls back down and reaches the ground, it's final downward velocity is 8.0 m/s. What wa

hram777 [196]

Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2

The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s

Using S=ut+
2
1

at
2

∴ S=30×3+
2
1

×(−10)×3
2
=45m

8 0

3 years ago

Read 2 more answers

How many orders of magnitude (powers of ten) is the distance to the moon greater than the distance across the Atlantic ocean?

kupik [55]

Answer:

The distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

Explanation:

We have the average distance across the Atlantic ocean, $d_i=3700\ mi$

the average distance to the moon, $d_m=238,900\ mi$

The factor by which the distance to moon is greater than the width of Atlantic ocean:

$f=\frac{d_m}{d_i}$

$f=\frac{238,900}{3700}$

$f=64.57$

i.e.

the distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

6 0

3 years ago

A heat engine takes in 840 kJ per cycle from a heat reservoir. Which is not a possible value of the engine's heat output per cyc

zhannawk [14.2K]

We have by the first law of thermodynamics tha energy is preserved, hence we cannot have over 840kJ per cycle. We have by the laws of thermodynamics (the 2nd one in specific) that the entropy of a system cannot increase. We cannot have an output of 840 kJ per cycle from a heat engine because then that would mean that the entropy would stay the same, while any heat engine increases it. Hence, any value $\geq 840 kJ$ is acceptable.

8 0

3 years ago