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3 years ago

How much work does the electric field do in moving a proton from a point with a potential of +130 V

Physics

1 answer:

In-s [12.5K]3 years ago

6 0

Explanation:

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What best describes the states of nonmetals when they are at room temperature? Most nonmetals are gaseous, but some are liquid o

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I think the correct answer from the choices listed above is the first option. The statement that best describes the state of metals when they are at room temperature would be that most <span>nonmetals are gaseous, but some are liquid or solid. Hope this answers the question. Have a nice day.</span>

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The ampere is a unit of which physical quantity?

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Newton’s law of gravitation says that gravity is a mutually attractive force. Explain the following observation: A small object

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Answer: See below

Explanation:

The Earth attracts the falling object with the same intensity of gravity as the object attracts the Earth, according to Newton's law of gravitation. The displacement of the two bodies, however, is inversely proportional to their respective masses.

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2 years ago

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What is the restoring force of a spring stretched 0.35 meters with a spring contact of 55 newtons?

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F=-kx = -19,25 answer D

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3 years ago

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In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha

Assoli18 [71]

Answer:

$\mathbf{v_a = 4.06 \times 10^7 \ m/s}$

Explanation:

$\text{The missing part of the question is attached below.} \\ \\ \text{ mass m = 4u and charge q = 2e. Suppose a uranium nucleus with 92 protons decays into }$ $\text{into thorium, with 90 protons, and an alpha particle. The alpha particle is initally at rest at }$ $\text{ the surface of the thorium nucleus, which is 15 fm in diameter. What is the speed of the alpha}$ $\text{particle when it is detected in the laboratory? Assume the thorium nucleus remains at rest. }$

$\text{So, from the above infromation;}$

$radius (r) = \dfrac{15 \ fm }{2}$

$radius (r) = 7.5 \times 10^{-15} \ m$

$\text{Using the formula for potential energy}$

$U = \dfrac{(9\times 10^9 \ Nm^2/C^2)(2(1.6\times10^{-19} \ C ))(90)(1.6\times 10^{-19} C)}{7.5 \times 10^{-13} \ m}$

$U = 5.529 \times 10^{-12} \ J$

$\text{Now, the speed of the alpha particle can be estimated from the conservation of energy principle}$ $\dfrac{1}{2}mv_a^2= 5.529 \times 10^{-12} J$

$v_a = \sqrt{\dfrac{2(5.529 \times 10^{-12} \ J)}{4(1.67 \times 106{-37} \ kg)}}$

$\mathbf{v_a = 4.06 \times 10^7 \ m/s}$

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2 years ago