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Leto [7]
3 years ago
8

A ray diagram is shown.

Physics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

  Z

Explanation:

The purple and yellow rays from the same point on the object are shown converging at point Z, where the image will be.

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Water is flowing at 4.0 m/s in a circular pipe. If the diameter of the pipe decreases to 1/2 of its former value, what is the ve
Montano1993 [528]

Answer:

v₂ = 16 m/s

Explanation:

We can use the continuity equation, which is as follows:

A_1v_1 = A_2v_2\\

where,

A₁ = Area of inlet = πd²/4

A₂ = Area of outlet = π(d/2)²/4 = πd²/16

v₁ = velocity at inlet = 4 m/s

v₂ = velocity at outlet = ?

Therefore,

(\frac{\pi d^2}{4})(4\ m/s)=(\frac{\pi d^2}{16})v_2\\\\

<u>v₂ = 16 m/s</u>

3 0
3 years ago
If the magnitude of the electric field in air exceeds roughly 3 ✕ 106 N/C, the air breaks down and a spark forms. For a two-disk
Westkost [7]

Answer:

1.843 x 10^-5 C  

Explanation:

<u><em>Givens:   </em></u>

It is given that the air starts ionizing when the electric field in the air exceeds a magnitude of 3 x 10^6 N/C, which means that the max electric field can stand without forming a spark is 3 x 10^6 N/C.  

Also it is given that the radius of the disk is 50 cm, it is required to find out the max amount of charge that the disk can hold without forming spark, which means the charge that would produce the max magnitude of the electric field that air can stand without forming spark, and since we know that the electric field in between 2 disk "Capacitor" is given by the following equation  

E = (Q/A)/∈o                                (1)

Where,

Q: total charge on the disk.

A: the area of the disk.  

<u><em>Calculations:  </em></u>

We want to find the quantity of charge on the disk that would produce an electric field of 3 x 10^6 N/C, knowing the radius of the disk we can find the cross-section of the disk, thus substituting in equation (1) we find the maximum quantity of charge the disk can hold  

Q = EA∈o

   = (3 x 10^6) x (π*0.50) x (8.85 x 10^-12)  

  = 1.843 x 10^-5 C  

note:

calculations maybe wrong but method is correct

8 0
3 years ago
When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C

Charge 2, q_2=+5.6\ \mu C=+5.6\times 10^{-6}\ C

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

F=k\dfrac{q_1q_2}{r^2}

r=\sqrt{\dfrac{kq_1q_2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times 8.4\times 10^{-6}\times 5.6\times 10^{-6}}{0.66}}

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.

4 0
3 years ago
A cylinder is filled with 10.0 L of gas and a piston is put into it. The initial pressure of the gas is measured to be 163. kPa.
alexgriva [62]

Answer:

P₂  = 370 kPa

Explanation:

Boyle's  law: States that the volume of a given mass of gas is inversely proportional to its pressure provided the temperature remains constant. It can be expressed mathematically as,

P₁V₁ = P₂V₂................ Equation 1

Where P₁ = Initial Pressure, V₁ = Initial volume, P₂ = Final Pressure, V₂ = Final Volume.

Making P₂ The subject of the equation above,

P₂ = P₁V₁/V₂..................... equation 2

Substituting these vaues into equation 2,

Where P₁ = 163 kPa = 163000 pa, V₁ =  10 L, V₂ = 4.4 L.

P₂ = 163000(10)/4.4

P₂ = 370454.55 Pa

P₂ = 370000 Pa

P₂  = 370 kPa To 3 significant figure.

Therefore Final pressure = 370 kPa

6 0
3 years ago
Elements that typically give up electrons
Bess [88]

Answer:

they are metals

Explanation:

they don't need to gain electrons they need to get rid of them

8 0
3 years ago
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