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natita [175]
2 years ago
13

A small plane starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds. What is the p

lane’s acceleration?
Please help!
Physics
1 answer:
Rainbow [258]2 years ago
3 0
Hope this helps, if you need clarification i got you

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To win the game, a place kicker must kick a
Dafna11 [192]

Answer:

1.86 m

Explanation:

First, find the time it takes to travel the horizontal distance.  Given:

Δx = 52 m

v₀ = 26 m/s cos 31.5° ≈ 22.2 m/s

a = 0 m/s²

Find: t

Δx = v₀ t + ½ at²

52 m = (22.2 m/s) t + ½ (0 m/s²) t²

t = 2.35 s

Next, find the vertical displacement.  Given:

v₀ = 26 m/s sin 31.5° ≈ 13.6 m/s

a = -9.8 m/s²

t = 2.35 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13.6 m/s) (2.35 s) + ½ (-9.8 m/s²) (2.35 s)²

Δy = 4.91 m

The distance between the ball and the crossbar is:

4.91 m − 3.05 m = 1.86 m

5 0
3 years ago
When in orbit, astronauts experience weightlessness what is this caused by?
erica [24]

no gravity or dark matter

4 0
3 years ago
Read 2 more answers
Un bloque de 25 n se encuentra suspendido por un hilo al techo vitamina la tensión que aparece en el hilo
SVETLANKA909090 [29]

Answer:

T = 25 N

Explanation:

The question says that "A 25 n block is suspended by a wire from the ceiling vitamin the tension that appears in the wire ?"

Weight of the block, W = 25 N

Weight of a body acts in downward direction and tension acts in upward direction. It would mean that,

Tension = weight of the block

T = mg

T = 25 N

Hence, the tension in the wire is 25 N.

7 0
2 years ago
Fill in the blank for four and five answer. Question for number 6.
ehidna [41]
Increase .... decrease .... presumably it's the "best shape" for a body which has been formed by the gravitational force
7 0
2 years ago
Consider steady heat transfer between two large parallel plates at constant temperatures of T1 = 210 K and T2 = 150 K that are L
snow_lady [41]

Answer:

Q=81.56\ W/m^2

Explanation:

Given that

T_1= 210 K

T_2= 150 K

Emissivity of surfaces(∈) = 1

We know that heat transfer between two surfaces due to radiation ,when both surfaces are black bodies

Q=\sigma (T_1^4-T_2^4)\ W/m^2

So now by putting the values

Q=\sigma (T_1^4-T_2^4)\ W/m^2

Q=5.67\times 10^{-8}(210^4-150^4)\ W/m^2

Q=81.56\ W/m^2

So rate of heat transfer per unit area

Q=81.56\ W/m^2

8 0
3 years ago
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