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STALIN [3.7K]
3 years ago
7

A point has length. true false user: lines have endpoints. true false

Mathematics
1 answer:
Katarina [22]3 years ago
3 0
False
false

point is 1 dimentional

lines are infinite

fals for both
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The graph of y=3x^2-3x-1 is shown. Use the graph to find estimates for the solutions of i)3x^2-3x+2=2 ii) 3x^2-3x-1=x+1
AlexFokin [52]

Answer:

i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).

Step-by-step explanation:

i) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = 2, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

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Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)

ii) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = x+1, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = x+1

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)

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andreev551 [17]

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Step-by-step explanation:

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Divide both sides by \log _{10}\left(5\right)

\frac{\log _{10}\left(5\right)\left(x^2-9\right)}{\log _{10}\left(5\right)}=\frac{0}{\log _{10}\left(5\right)}

Simplify

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Add 9 to both sides

x^2-9+9=0+9

Simplifying

x^2=9

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{9},\:x=-\sqrt{9}

as

\sqrt{9}\:=3

-\sqrt{9}=-3

Therefore,

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