A planet has a mass of 5.68 x 1026 kg and a radius of 6.03 x 107 m. What is the weight of a 65.0 kg person on the surface of thi
1 answer:
To solve this problem, we must know the gravitational force of the planet. The equation would be,
This would calculate the force between two objects with masses m1 and m2 and the gravitational constant, G, is 6.67 x 10^-11 m3 s-2 kg-1 and with r as the distance between the objects.
Thus,
F = (6.67 x 10^-11 m3 s-2 kg-1) * (5.68 x 10^26 kg) * (65 kg) * ((1/6.03 x 10^7 m)^2)
F = 678 kg/s^2 or 678 N
Answer is letter B.
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Answer: -1.91*10^13 v/m
Explanation:
A string with linear density 0.500 g/m.
Tension 20.0 N.
The maximum speed
The energy contained in a section of string 3.00 m long as a function of .
We are given following data for string with linear density held under tension :
μ = 0.5
= 0.5 x 10⁻³
T = 20 N
If string is L = 3m long, total energy as a function of is given by:
E = 1/2 x μ x L x ω² x A²
= 1/2 x μ x L x
= 7.5 x 10⁻⁴
So, The total energy as a function of = 7.5 x 10⁻⁴
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