A planet has a mass of 5.68 x 1026 kg and a radius of 6.03 x 107 m. What is the weight of a 65.0 kg person on the surface of thi
1 answer:
To solve this problem, we must know the gravitational force of the planet. The equation would be,
This would calculate the force between two objects with masses m1 and m2 and the gravitational constant, G, is 6.67 x 10^-11 m3 s-2 kg-1 and with r as the distance between the objects.
Thus,
F = (6.67 x 10^-11 m3 s-2 kg-1) * (5.68 x 10^26 kg) * (65 kg) * ((1/6.03 x 10^7 m)^2)
F = 678 kg/s^2 or 678 N
Answer is letter B.
You might be interested in
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that charge density is the ratio of total charge and total volume
So here the volume of the charge ball is given as
now the charge density of the ball is given as
Part b)
Now the charge enclosed by the surface is given as
at radius of 5 cm
at radius of 10 cm
at radius of 20 cm
Part c)
As we know that electric field is given as
so we have electric field at r = 5 cm
electric field at r = 10 cm
electric field at r = 20 cm
Missing question: "What is the spring's constant?"
Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
And by using Hook's law, we can find the constant of the spring:
Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
And by using Hook's law, we can find the constant of the spring: