Question

Please show your work - thank you! :)

Answer 1

Answer:

A. 4500 mL

Explanation:

We need to use a version of the combined gas law, which states:

$\frac{V_1}{n_1T_1}= \frac{V_2}{n_2T_2}$ , where T represents temperature, V volume, and n moles

First, look at the initial values of n, V, and T:

- n: we have 10.0 grams of hydrogen, which we need to convert to moles. So: $10.0g*\frac{1 mol}{2.02 g} =4.95molH_2$

- V: we have a volume of 5.0 L

- T: our temperature right now is 28.0°C, but we need it in Kelvins, so add 273: 28.0 + 273 = 301 K

Now look at the final values:

- n: our final number of grams is 8.5 grams of hydrogen, so we need to convert this to moles.

$8.5g*\frac{1 mol}{2.02 g} =4.2molH_2$

- V: this is what we want to find

- T: our final temperature is 44.0°C; to convert it to Kelvins, add 273.

44.0 + 273 = 317 K

Put this altogether:

$\frac{V_1}{n_1T_1}= \frac{V_2}{n_2T_2}$

$\frac{5.0}{4.95*301}= \frac{V_2}{4.2*317}$

Multiply both sides by (4.2 * 317):

$V_2$ ≈ 4.5 L

However, the problem wants millilitres, so simply multiply 4.5 by 1000:

4.5 * 1000 = 4500

The answer is thus A.