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2 years ago

Which of the following statements is true?

Chemistry

2 answers:

zalisa [80]2 years ago

6 0

It's A, t<span>The figure is a molecule and an element.</span>

zhuklara [117]2 years ago

4 0

The answer is A. The figure is a molecule and an element. You're welcome

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Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions

Veronika [31]

Answer:

][H

]

[NH

]

+3H

⇌2NH

(1.5×10

−2

)(3×10

−2

)

(1.2×10

−2

)

1.5×10

−2

×27×10

−6

1.44×10

−4

40.5×10

−4

1.44

=0.035×10

5 0

2 years ago

Which organelles surround the cell?

GalinKa [24]

Answer:

Cell Wall, Cell Membrane, Nucleus, Endoplasmic Reticulum (ER), and Ribosome.

Explanation:

Hopefully this helps :).

5 0

3 years ago

Read 2 more answers

The compound Xe(CF3)2 decomposes in afirst-order reaction to elemental Xe with a half-life of 30. min.If you place 7.50 mg of Xe

Irina-Kira [14]

Answer:

$t=147.24\ min$

Explanation:

Given that:

Half life = 30 min

$t_{1/2}=\frac{\ln2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30}\ min^{-1}$

The rate constant, k = 0.0231 min⁻¹

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given that:

The rate constant, k = 0.0231 min⁻¹

Initial concentration $[A_0]$ = 7.50 mg

Final concentration $[A_t]$ = 0.25 mg

Time = ?

Applying in the above equation, we get that:-

$0.25=7.50e^{-0.0231\times t}$

$750e^{-0.0231t}=25$

$x=\frac{\ln \left(30\right)}{0.0231}$

$t=147.24\ min$

6 0

3 years ago

Upon arrival we needed to hunt in this new land we only had five refills and they needed 50 g of gunpowder to be shot once. We o

emmasim [6.3K]

Answer:

Explanation:

Upon arrival we needed to hunt in this new land we only had five refills and they needed 50 g of gunpowder to be shot once. We only have 15 pounds of gunpowder. It is taking six shots to kill one of these wild turkeys. How many turkeys can be shot with 15 pounds of gunpowder?

If we had plenty of refills, and it takes 6 shots to kill a wild turkey at 50 gms of gunpowder per shot, then each turkey requires 6X50 =300gms of gunpowder. We have 15X454 gms of gunpowder and have the potential to kill 15X454/300=22.7 or 22 turkeys.and it takes 6 shots to kill a wild turkey.

The limiting reagent is the number of refills, and withonly 5, we are out of luck and can't kill one turkey

6 0

2 years ago

How many moles of hypomanganous acid. H3 MnO4, are contained in 22.912 g?

gregori [183]

Answer:

0.188mol

Explanation:

Using the formula;

mole = mass/molar mass

Molar mass of hypomanganous acid. (H3MnO4) = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

According to this question, there are 22.912g of H3MnO4

mole = 22.912g ÷ 122g/mol

mole = 0.188mol

6 0

3 years ago