NewtonsXmeters / time is a unit of which of the following:

A person jumped off a cliff, what would happen?

Anastaziya [24]

Death would happen, hope this helped

8 0

2 years ago

You are trying to overhear a most interesting conversation, but from your distance of 10.0 m , it sounds like only an average wh

Alexandra [31]

Answer:

r₂=0.1 m

Explanation:

Given that

r₁= 10 m , β₁ = 20 dB

At r₂ ,β₂= 60 dB

As we know that intensity level of sound given as

$\beta =10\ log\dfrac{I}{10^{-12}}$

$\beta _1=10\ log\dfrac{I_1}{10^{-12}}$

$20=10\ log\dfrac{I_1}{10^{-12}}$

10² x 10⁻¹² = I₁

I₁=10⁻¹⁰ W/m²

$\beta _2=10\ log\dfrac{I_2}{10^{-12}}$

$60=10\ log\dfrac{I_1}{10^{-12}}$

10⁶ x 10⁻¹² = I₂

I₂ = 10⁻⁶ W/m²

I₁=10⁻¹⁰ W/m²

P = I A

P=Power ,I =Intensity ,A=Area

$\dfrac{I_1}{I_2}=\dfrac{r^2_2}{r^2_1}$

$\dfrac{10^{-10}}{10^{-6}}=\dfrac{r^2_2}{10^2}$

r₂=0.1 m

4 0

2 years ago

PLEASE ANSWER You are in a vehicle waiting at a railroad crossing and notice a train going by at a constant speed of 5 kph. You

Dominik [7]

Reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

5 0

2 years ago

Read 2 more answers

A plane monchromatic radio wave (lambda = 0.3 m) travels in vacuum along the positive x-axis, with an intensity I = 45 W/m2. Sup

Harrizon [31]

Answer:

$-5.78414\times 10^{-6}\ T$

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

$\lambda$ = Wavelength = 0.3 m

T = Time period

f = Frequency

$E_0$ = Electric field

Intensity of electric field is given by

$I=\dfrac{1}{2}c\epsilon_0E_0^2\\\Rightarrow E_0=\sqrt{\dfrac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\dfrac{2\times 45}{3\times 10^{8}\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=184.11492\ N/C$

Magnetic field is given by

$B_0=\dfrac{E_0}{c}\\\Rightarrow B_0=\dfrac{184.11492}{3\times 10^8}\\\Rightarrow B_0=6.13716\times 10^{-7}\ T$

$k=\dfrac{2\pi}{\lambda}\\\Rightarrow k=\dfrac{2\pi}{0.3}\\\Rightarrow k=20.94\ /m$

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^{8}}{0.3}\\\Rightarrow f=1\times 10^{9}\ Hz$

$T=\dfrac{1}{f}\\\Rightarrow T=10^{-9}$

$\omega=\dfrac{2\pi}{T}\\\Rightarrow \omega=\dfrac{2\pi}{10^{-9}}\\\Rightarrow \omega=6283185307.17958\ rad/s$

Magnetic field in the z direction is given by (x=0)

$B_z=B_0(kx-\omega t)\\\Rightarrow B_z=6.13716\times 10^{-7}\times (0-6283185307.17958\times 1.5\times 10^{-9})\\\Rightarrow B_z=-5.78414\times 10^{-6}\ T$

The magnetic field at the origin is $-5.78414\times 10^{-6}\ T$

4 0

3 years ago

A coin with a diameter of 2.40 cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular spee

posledela

Answer:

The coin comes to rest after covering 1.023 m.

Explanation:

initial angular speed, wo = 18 rad/s

final angular speed, w = 0 rad/s

angular acceleration, = 1.9 rad/s2

radius, r = 1.2 cm = 0.012 m

initial linear velocity, u = r wo = 0.012 x 18 = 0.216 m/s

final linear speed, v = r w = 0.012 x 0 = 0 m/s

linear acceleration, a = r x angular acceleration = 0.012 x 1.9 = 0.0228 m/s2

let the distance traveled is s.

Use third equation of motion

$v^{2} = u^{2} + 2 a s\\0 = 0.216^{2} - 2 \times 0.0228\times s\\s = 1.023 m$

4 0

2 years ago