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Natasha_Volkova [10]
3 years ago
13

Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as sh

own below. The spring constant is k=95.5\,\dfrac{\text N}{\text m}k=95.5 m N ​ k, equals, 95, point, 5, start fraction, start text, N, end text, divided by, start text, m, end text, end fraction. The block is moved rightwards and the spring's right end is displaced from the position of 0.200\,\text m0.200m0, point, 200, start text, m, end text to 0.220\,\text m0.220m0, point, 220, start text, m, end text where it is held in place. All positions are measured from the origin OOO of the wall. What is the spring force exerted on the block?
Physics
1 answer:
puteri [66]3 years ago
8 0

Answer:

F = 19.1 N

Explanation:

To find the force exerted by the string on the block you use the following formula:

F=kx  (1)  

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

F=(95.5N/m)(0.200m)=19.1N

Hence, the force exterted on the block is 19.1 N

 

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Afor:6000Nm

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3.Three resistors of 25.0Ω, 30.0Ω, and 40.0Ω are in a series circuit with a 6.0-volt battery. What is the current in the circuit
AURORKA [14]

Answer:

Current = 0.063 Amperes

Explanation:

Let the three resistors be R1, R2, and R3 respectively.

Given the following data;

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R2 = 30.0Ω

R3 = 40.0Ω

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First of all, we would determine the equivalent or total resistance;

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Total resistance = 25.0Ω + 30.0Ω + 40.0Ω

Total resistance = 95 Ω

Next, we find the current flowing through the circuit;

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Substituting into the formula, we have;

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Answer:

a) 0 J

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The amount of heat is equal to the work done W

d)

\Delta U = \Delta Q-W\\\\0=\Delta Q-W\\\\\Delta Q=W=nRTln(\frac{V_f}{V_i})

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