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Natasha_Volkova [10]
3 years ago
13

Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as sh

own below. The spring constant is k=95.5\,\dfrac{\text N}{\text m}k=95.5 m N ​ k, equals, 95, point, 5, start fraction, start text, N, end text, divided by, start text, m, end text, end fraction. The block is moved rightwards and the spring's right end is displaced from the position of 0.200\,\text m0.200m0, point, 200, start text, m, end text to 0.220\,\text m0.220m0, point, 220, start text, m, end text where it is held in place. All positions are measured from the origin OOO of the wall. What is the spring force exerted on the block?
Physics
1 answer:
puteri [66]3 years ago
8 0

Answer:

F = 19.1 N

Explanation:

To find the force exerted by the string on the block you use the following formula:

F=kx  (1)  

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

F=(95.5N/m)(0.200m)=19.1N

Hence, the force exterted on the block is 19.1 N

 

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Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of
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Answer:

r = 0.0548 m

Explanation:

Given that,

Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities.

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r=\dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}

m is mass of Singly charged uranium-238 ion, m=3.95\times 10^{-25}\ kg

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So,

r=\dfrac{1}{1.9}\times \sqrt{\dfrac{2\times 3.95\times 10^{-25}\times 2.2\times 10^3}{1.6\times 10^{-19}}}\\\\r=0.0548\ m

So, the radius of their circular path is equal to 0.0548 m.

4 0
3 years ago
What is the final speed?
EastWind [94]
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t=3.4s
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6 0
3 years ago
3. In some countries AC outlets near bathtubs are restricted to a maximum of 25 V to minimize the chance of dangerous shocks whi
Ierofanga [76]

Answer:

The answer is below

Explanation:

The average resistivity of the human body (apart from surface resistance of the skin) is about 5.0 Ωm. The conducting path between the right and left hands can be approximated as cylinder 1.6 m long and 0.10 m in diameter. The skin resistance can be made negligible by soaking the hands in salt water. (a) What is the resistance between the hands if the skin resistance is negligible? (b) if skin resistance is negligible, what potential difference between the hands is needed for lethal shock current 100 mA?

Solution:

The resistance (R) of a material is given by the formula:

R = ρL / A

where L is the length of the conductor, ρ is resistivity and A is the cross sectional area.

a) R = ρL / A

ρ = 5.0 Ωm, L = 1.6 m, A = π(diameter²) / 4 = π(0.1²)/4 = 0.00785 m²

R = 5(1.6) / 0.00785 = 1018.6 ohm

b) To produce 100 mA, we need to use ohms law:

I = 100 mA = 0.1 A, R = 1018.6 ohm

V = IR = 0.1(1018.6)

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7 0
2 years ago
Anne applies a force on a toy car and makes it move forward. What can be said about the forces acting on the toy car at the mome
tester [92]

The correct answer to the question is unbalanced .

EXPLANATION:

As per Newton's first laws of motion, we know that a body at rest will be at rest or a body moving with uniform velocity along a straight line will keep on moving with the same velocity along that line unless and until it is compelled by some external unbalanced forces acting on.

Hence, it is the unbalanced force which is responsible for creating the motion on the body.

As per the question, Anne applied some force on the toy car. It is called applied force. There is also frictional force between car and the surface which opposes the motion of the car. The toy car will move due to the net force acting on it. The net force is known as unbalanced force.

5 0
3 years ago
Read 2 more answers
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