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lora16 [44]
4 years ago
8

PROVE THAT G = GM/R² WHERE THE SYMBOLS HAS THEIR USUAL MEANINGS​

Physics
1 answer:
butalik [34]4 years ago
8 0

Answer:

g=GM/R^2

Universal Gravutation Constant:

f=GM×m/R^2

Force can be also expressed as

f=m×g

so,

mg=GMxm/R^2

The m gets cancelled so

g=GM/R^2

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The semi-circular canals match the description. Therefore, it is the answer.

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3 years ago
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4 years ago
Write down the DE of this damped harmonic oscillator.
ohaa [14]

Answer:

\frac{d^{2}x }{d^{2}t }+\frac{k}{m}x+\frac{b}{m} \frac{dx}{dt}=0

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F=-kx-bv

Here, -bv is the damping term used in this b is damping constant, k is spring constant, x is elongation in the spring, F is the force.

ma=-kx-bv\\m\frac{d^{2}x }{d^{2}t }=-kx-b\frac{dx}{dt}\\  m\frac{d^{2}x }{d^{2}t }+kx+b\frac{dx}{dt}=0\\\frac{d^{2}x }{d^{2}t }+\frac{k}{m}x+\frac{b}{m} \frac{dx}{dt}=0

Therefore the differential equation for the damped harmonic oscillator is,

\frac{d^{2}x }{d^{2}t }+\frac{k}{m}x+\frac{b}{m} \frac{dx}{dt}=0

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