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olasank [31]
3 years ago
14

A marble rolls along the floor with a constant velocity of 6 m/s. How far will it have gone after 130 seconds

Physics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Answer:

0.046

Explanation:

displacement = velocity/ time

d = 6m/s / 130s

d = 0.046m

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1. The law of reflection states that the angle of _______ is equal to the angle ofreflection
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Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much
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Answer:

T = 6.75\,N\cdot m

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

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8 0
3 years ago
A cat is shot horizontally out of a cannon that is on top of a 125 meter tall cliff. If the cat lands 286 m away from the base o
Elden [556K]

The initial velocity of the cat is 56.6 m/s

Explanation:

The motion of the cat is a projectile motion, consisting of:

- a uniform horizontal motion with constant velocity

- a vertical accelerated motion with constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:

s=ut+\frac{1}{2}at^2

where we have (choosing downard as positive direction)

s = 125 m is the vertical displacement of the cat

u = 0 is the initial vertical velocity

t is the time taken to reach the ground

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(125)}{9.8}}=5.05 s

Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by

v_x =\frac{d}{t}

where

d = 286 m is the horizontal distance travelled

t = 5.05 s is the time taken

Solving the equation,

v_x = \frac{286}{5.05}=56.6 m/s

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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3 years ago
A paperboy rode his bike 3m/s. After being chased by a dog for 8 seconds he was traveling 6m/s. What is his accleration
aev [14]
I believe the answer is 0.375 m/s²
8 0
3 years ago
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