A plane traveling 40 m/s drops a box from a height of 186 m. Where does the box strike the ground relative to the point directly
1 answer:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The workdone is
Explanation:
From the question we are told that
The initial Volume is
The final volume is
The external pressure is
Generally the change in volume is
Substituting values we have
Generally workdone is mathematically represented as
W is negative because the working is done on the environment by the system which is indicated by volume increase
Substituting values
Now
Therefore
Answer:
0.000234 seconds
Explanation:
Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m
We can start by calculating the angular speed of the rod:
Since one revolution equals to 2π rad. The speed in revolution per second must be
26800 / 2π = 4265 revolution/s
The number of seconds per revolution, or period, is the inverse:
1/4265 = 0.000234 seconds
<h2>Hello!</h2>
The answer is: 19.59 m
<h2>Why?</h2>Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.
When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:
We will use the following formula:
Where:
Vf= Final velocity = 0
Vi= Initial velocity =
g = Gravity Acceleration =
s = Traveled distance
Have a nice day!