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bogdanovich [222]
3 years ago
14

A plane traveling 40 m/s drops a box from a height of 186 m. Where does the box strike the ground relative to the point directly

below where it was released?
What is the horizontal velocity just before the box hits?
What is the vertical velocity just before it hits? Take upward to be positive.
Physics
1 answer:
Arte-miy333 [17]3 years ago
8 0

Answer:the horizontal velocity is 40

Explanation:

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no links never ever in the world give me a link just answer now without links What is the lithosphere? please write a full parag
nasty-shy [4]

Answer:

the solid outerpart of the earth

5 0
3 years ago
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A point charge has q=1.0×10-6
dmitriy555 [2]

Since the 2 points form a triangle with hypothenuse of √5 [ √(1²+2²)],

I guess apply the formula :

v = kq \div r

with r as √5 and q as 1x10^-6

not sure about this answer tho

draw a diagram first to understand better

8 0
3 years ago
Total energy input is 1400 and my efficiency is 80% so what is the useful energy output in jules?
Ierofanga [76]

Answer

1400 * 0.8 = 1,120

the useful energy output is 1,120 joules

4 0
3 years ago
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end
ozzi

Answer:

The total work that the rope does to Mangnus is - 5780 Jules.

Explanation:

By definition, the work is defined as:

W=F.d

Where F and d are the force and the total displacement. Note that in the definition the product is a scalar product since F and d are both vectors.  

Take into account that according to third Newton's law the force that the rope does to Magnus is opposite to the force that Magnus does to the rope, therefore the scalar product will be negative due the rope's force goes against to Magnus displacement.  

For calculating the work, we take 2500 N as the value for the force and 2.312 meters as the value for the displacement:

W=-2500 N * 2.312 m

W=-5780 Nm = -5780 J

7 0
3 years ago
Assuming 100% efficient energy conversion, how much water stored behind a 50 centimetre high hydroelectric dam would be required
11Alexandr11 [23.1K]

Complete question is;

Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes

Answer:

Amount of water required to charge the battery = 7.35 m³

Explanation:

The formula for Potential energy of the water at that height = mgh

Where;

m = mass of the water

g = acceleration due to gravity = 9.8 m/s²

H = height of water = 50 cm = 0.5 m

We know that in density, m = ρV

Where;

ρ = density of water = 1000 kg/m³

V = volume of water

So, potential energy is now given as;

Potential energy = ρVgH = 1000 × V × 9.8 × 0.5 = (4900V) J

Now, formula for energy of the battery is given as;

E = qV

We are given;

q = 50 A.min = 50 × 60 = 3,000 C

V = 12 V

Thus;

qV = 3,000 × 12 = 36,000 J

E = 36,000 J

At a 100% conversion rate, the energy of the water totally powers the battery.

Thus;

(4900V) = (36,000)

4900V = 36,000

V = 36,000/4900

V = 7.35 m³

5 0
3 years ago
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