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laiz [17]
3 years ago
10

Use the equation v = h - 6 to find the value of v when h = 9.

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

oint variation problems are solved using the equation y = kxz. ... Step 2: Use the information given in the problem to find the value of k, called the ... Example 1 – If y varies jointly as x and z, and y = 12 when x = 9 and z = 3, find z when y = 6 and x = 15. ... In this case, you need to find k when v = 120π, h = 10, and r = 6. Step 2.

Step-by-step explanation:

Marysya12 [62]3 years ago
6 0

V= 9-6
Answer V=3
If you have any questions lmk!
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write an equation to find the amount of simple interest, earned on a 600 dollar investment after 9 months, of the interest rate
tatuchka [14]

Equation:
A = P(1 + rt)
How to do it:
First, converting R percent to r a decimal
r = R/100 = 2.5%/100 = 0.025 per year,
putting time into years for simplicity,
9 months ÷ 12 months/year = 0.75 years,
then, solving our equation
A = 600(1 + (0.025 × 0.75)) = ___
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What is the measure of ∠K?
Ierofanga [76]
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3 years ago
Mya and ERIC WORK IN A BAKERY . MYA HAS 3 TIMEA AS MUCH FLOUR AS ERIC .MYA HAS 15.81LB OF FLOUR .USE THE EQUATION 3F = 15.81 TO
Pavel [41]

Answer:

5.27 lb

Step-by-step explanation:

Given that,

Mya has 3 times as much floor as Eric. Mya has 15.81 lb of floor. The relation is given by :

Let Eric has F floor.

3F = 15.81 ...(1)

We need to find how much flour Eric has.

Dividing both sides by 15.81.

F = 15.81/3

F = 5.27 lb

Hence, Eric has 5.27 lb of flour.

4 0
3 years ago
Convert percents to fractions (Write the answer in SIMPLEST FORM)
Grace [21]
1/4;2/5;83/100;3/2;7/10;4/5
5 0
3 years ago
In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
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