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3 years ago

If you have an oily or saturated absorbent pad after refueling at a marina fuel dock, what is the best thing to do with it?

1 answer:

5 0

<span>If you have an oily or saturated absorbent pad after refueling at a marina fuel dock then the best thing to do with it is:

1) To clean up the spills of fuel immediately with oily or saturated absorbent pad.

2) Moreover, the interior parts of the fuel which are in contact with the fuel should be wiped with the saturated absorbent pad.</span>

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Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s

Lera25 [3.4K]

Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.

Explanation:

8 0

3 years ago

A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the m

Paraphin [41]

Answer:

I2>I1

Explanation:

This problem can be solved by using the parallel axis theorem. If the axis of rotation of a rigid body (with moment of inertia I1 at its center of mass) is changed, then, the new moment of inertia is gven by:

$I_2=I_{1}+Md^2$

where M is the mass of the object and d is the distance of the new axis to the axis of the center of mass.

It is clear that I2 is greater than I1 by the contribution of the term Md^2.

I2>I1

hope this helps!!

8 0

3 years ago

Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal gorces what is the wagons

kicyunya [14]

Answer:

$a=3m/s^2$

Explanation:

If we have a net force F acting on a body of mass m it will experiment an acceleration a. Newton's 2nd Law gives us the relation between these quantities: F=ma.

In our case, we want to calculate the acceleration, so we write:

$a=\frac{F}{m}$

With the values we have we get:

$a=\frac{30N}{10Kg}=3m/s^2$

3 0

3 years ago

PLEASE HELP WITH EXPLANATION! I WILL GIVE YOU BRAINLIEST!

DiKsa [7]

Answer:

divide the distance by the time and get average velocity in units of s. the detection to the left

6 0

3 years ago

A ball of mass 0.15 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. b)

Art [367]

Answer:

Explanation:

If v be the velocity just after the rebound

Kinetic energy will be converted into potential energy

1/2 m v² = mgh

v² = 2gh

v = √ 2gh

= √ 2 x 9.8 x .96

= 4.33 m / s

4 0

3 years ago