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3 years ago

What is a simple definition of atom, particle, and kinetic?

Chemistry

1 answer:

JulsSmile [24]3 years ago

4 0

Answer:

Atom: The smallest particle of an element that has the properties of the element and can exist either alone or in combination.

Particle: One of the very small parts of matter (as a molecule, atom, or electron)

Kinetic: Of or relating to the motions of material bodies and the forces and energy associated with them

Explanation:

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During chemical reactions the bonds between atoms break and new bonds form. Energy must be absorbed to break a bond, so breaking

ss7ja [257]

Answer:

The equation is: CuCO3(s) → CuO(s) + CO2(g)

Explanation:

Copper carbonate decomposes at high temperatures, generating the products carbon dioxide (CO2) and copper oxide (II) CuO. In this type of decomposition reaction, a substance is broken generating two different compounds.

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3 years ago

What happens when an acid reacts with a base?

shepuryov [24]

Answer:

They neutralize each other

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2 years ago

Read 2 more answers

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vazorg [7]

Answer:

A. 1, 2, 5

Explanation:

Count the number of Ns in the formula.

- Hope that helped! Please let me know if you need a further explanation.

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2 years ago

Which of these statements are not true about a chemical reaction rate?

Licemer1 [7]

A) Temperature does not affect reaction rate

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2 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

lions [1.4K]

Answer: The equilibrium concentration of $COF_2$ is 0.332 M

Explanation:

We are given:

Initial concentration of $COF_2$ = 2.00 M

The given chemical equation follows:

$2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)$

Initial: 2.00

At eqllm: 2.00-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}$

We are given:

$K_c=6.30$

Putting values in above expression, we get:

$6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25$

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of $COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M$

Hence, the equilibrium concentration of $COF_2$ is 0.332 M

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3 years ago