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Vika [28.1K]
3 years ago
9

According to the Pauli exclusion principle, when can two electrons occupy the same orbital?

Chemistry
1 answer:
Lyrx [107]3 years ago
3 0
C.

For electrons to occupy the same orbital, every other orbital in the sub shell must have at least one electron and the paired electrons must have opposite spins.
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2. Which of the following is true about the total number of reactants and the total number of
Soloha48 [4]

9 moles of reactants chemically change into 11 moles of product.

Explanation:

In the reaction above, 9 moles of reactants chemically change into 11 mole of products. The coefficients in a reaction is the number of moles of the reacting atoms .

  • For example 8O₂ depicts 8 moles of two oxygen atoms.
  • The number of moles  is a unit for quantifying particles.
  • You can liken it to a dozen, gross or a score.
  • Since a mole of a substance contains avogadro number of particles. We can relate the number of moles to other parameters.

Learn more:

Moles brainly.com/question/2272966

#learnwithBrainly

8 0
2 years ago
Read 2 more answers
To what category of elements does an element belong if it's a poor conductor of electricity
Karo-lina-s [1.5K]

Answer:

I would assume NON-METALS

7 0
3 years ago
Can someone please help me with this?
yaroslaw [1]

Answer:

Lonic.an electron will be transferred from potassium to the chlorine atom

3 0
3 years ago
Read 2 more answers
I need help, plz help me with this problem
Svetlanka [38]

Answer:

It's b

Explanation:

I had the same exact question

5 0
2 years ago
When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu
Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0
3 years ago
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