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3 years ago

Can any juniors who go to Texas connections academy help me out with physics?

Physics

1 answer:

zimovet [89]3 years ago

3 0

I'm not from that school but I can help you.

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3. A car does an emergency stop from 144 km\h in 4s<br> What was its deceleration?

strojnjashka [21]

Answer:

36?

Explanation:

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2 years ago

I don’t get how to answer the questions.

Dominik [7]

Write the answer below the question?

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3 years ago

Which of the following is the most reasonable weight in units of newtons for an average adult?

Oliga [24]

Answer: The reason weight for average adult is 530N

Explanation: The clearly see this answer, let's convert this weight to kg using F=mg

530=m×9.8

g is a constant of 9.8m/s2

We divide both sides by 9.8 to get

54kg then this weight is reasonable for an average adult.

7 0

3 years ago

Read 2 more answers

Two tiny particles having charges 20.0 μC and 8.00 μC are separated by a distance of 20.0 cm What are the magnitude and directio

Alecsey [184]

Answer:

The magnitude and direction of electric field midway between these two charges is $10.8\times10^{5}\ N/C$ along AB.

Explanation:

Given that,

First charge $q_{1}= 20\mu C$

second charge $q_{2}= 8\mu C$

Distance = 20 cm

We need to calculate the electric field

For first charge,

Using formula of electric field

$E_{1}= \dfrac{kq_{1}}{r^2}$

Put the valueinto the formula

$E_{1}=\dfrac{9\times10^{9}\times20\times10^{-6}}{10\times10^{-2}}$

$E_{1}=18\times10^{5}\ N/C$

Direction of electric field along AB

We need to calculate the electric field

For second charge,

Using formula of electric field

$E_{2}= \dfrac{kq_{2}}{r^2}$

Put the valueinto the formula

$E_{2}=\dfrac{9\times10^{9}\times8\times10^{-6}}{10\times10^{-2}}$

$E_{2}=7.2\times10^{5}\ N/C$

Direction of electric field along AO

We need to calculate the net electric field at midpoint

$E_{net}=E_{1}-E_{2}$

$E_{net}=(18-7.2)\times10^{5}\ N/C$

$E_{net}=10.8\times10^{5}\ N/C$

Direction of net electric field along AB

Hence, The magnitude and direction of electric field midway between these two charges is $10.8\times10^{5}\ N/C$ along AB.

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3 years ago

6. Willingness to take turns is one way we can express our attitudes in

NNADVOKAT [17]

The answer is A ..........

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3 years ago