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Oduvanchick [21]
2 years ago
9

Is silver magnetic or not ?

Physics
1 answer:
evablogger [386]2 years ago
4 0

Answer:

Yes, but its magnetic power is very weak so its not that noticeable to the average person whos not paying attention.

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A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy.
statuscvo [17]
Internal energy of the system changes by ΔE = 178 J.
Heat given to the system = Q = +658 J.

According to the first law of thermodynamics, 
ΔE = Q + W
178 = 658 + W 
∴ W = 178-658 = -480 J

Minus sign indicates that work is done by the system. 
7 0
3 years ago
Read 2 more answers
Which statement about subatomic particles is true?
navik [9.2K]

A. An electron has far less mass than either a proton or neutron.

4 0
3 years ago
Adding more pulleys to a system of pulleys _____ needed to lift an object.
-Dominant- [34]

I think it’s D-decreases the amount of work.

3 0
2 years ago
A student evaluates a weight loss program by calculating the number of times he would need to climb a 14.0 m high flight of step
Liula [17]

Answer:

400 trips

Explanation:

Mechanical energy needed to climb 14 m by a man of 68 kg

= mgh

= 68 x 9.8 x 14

= 9330 J

1 Kg of fat releases 3.77 x 10⁷ J of energy

.45 kg of fat releases 1.6965 x 10⁷ J of energy

22% is converted into mechanical energy

so 22% of 1.6965 x 10⁷ J

= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.

one trip of climbing of 14 m requires 9330 J of mechanical energy

no of such trip possible with given mechanical energy

= 3732.3 x 10³ / 9330

= 400 trips

7 0
3 years ago
The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed
galben [10]

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ \angle BCA = (90-30)

⇒             =60^{\circ}

then,

⇒ \angle BAC=(180-45-60)

⇒             =75^{\circ}

Now,

The corresponding angle will be:

⇒ \angle FAC=60^{\circ}

⇒ \angle FAB=70+60

⇒             =135^{\circ}

Aspect of F across the AC arm will be:

= F\times cos(60)

On putting the values of F, we get

= 500\times (.5)

= 200 \ Newton

Component F along the AC (in magnitude) will be:

= F\times cos(135)

= 500\times (-.707)

= -353.5 \ N \

4 0
2 years ago
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