When 0.1 M HNO₃ is added to water it dissociates as follow,
HNO₃ → H₃O⁺ + NO₃⁻
Let us calculate the pH of this acid in order to know its strength,
As,
pH = -log [H₃O⁺]
Putting H⁺ concentration value,
pH = -log [0.1]
pH = 1
It is highly acidic,
And being strong acid it completely ionizes in water producing only H₃O⁺ and NO₃⁻.
So,
The concentration of H₃O⁺ = 0.1 M
and,
The concentration of NO₃⁻ = 0.1 M
Answer:
8.934 g
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 192.12 44.01
H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂
m/g: 13.00
For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.
(a) Calculate the <em>moles of H₃Cit
</em>
n = 13.00 g × (1 mol H₃Cit /192.12 g H₃Cit)
n = 0.067 67 mol H₃Cit
(b) Calculate the <em>moles of CO₂
</em>
The molar ratio is (3 mol CO₂/1 mol H₃Cit)
n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)
n = 0.2030 mol CO₂
(c) Calculate the <em>mass of CO₂
</em>
m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)
m = 8.934 g CO₂
<h3><u>Answer;</u></h3>
Nitrogen (N)
<h3><u>Explanation;</u></h3>
- Atoms may lose or gain electrons to achieve stability. Metal atoms lose electrons to attain stable configuration, and as a result they form positively charged ions called cations.
- <u>Non-metals on the other hand gain electrons to attain stable configuration, and as a result form negatively charged ions called anions.</u>
- <u>Among the elements given above nitrogen (N) gains electrons to form a negatively charged ion called anion. </u>
(C) NaNO3
Cant be A,B,orD not suitable
Answer:
The temperature at which each bean is kept
Explanation:
Independent variable is what YOU CHANGE