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4 years ago

LiOH + KCI → LiCl + KOH

Chemistry

1 answer:

yulyashka [42]4 years ago

3 0

Answer:

35.42g

Explanation:

LiOH + KCI → LiCl + KOH

Let us determine the molar mass of LiOH and LiCl. This is illustrated below:

Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol

Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.

Now, we can obtain the theoretical yield of LiCl as follow:

From the equation above,

24g of LiOH reacted to produce 42.5g of LiCl.

Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.

From the above calculations, the theoretical yield of LiCl is 35.42g

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3 years ago

Consider this equilibrium: HCO31- + H2PO41- HPO42- + H2CO3. What are the Brønsted-Lowry acids in this equilibrium?

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3 years ago

Read 2 more answers

The molar heat capacity of a compound with the formula C2H6SO is 88.0 J/mol-K. The specific heat of this substance is __________

lisabon 2012 [21]

Answer : The specific heat of this substance is, 1.13 J/g.K

Explanation :

Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.

As we are given that the chemical formula of compound is, $C_2H_6SO$

First we have to calculate the molar mass of given compound.

Molar mass of $C_2H_6SO$ = $2(12g/mol)+6(1g/mol)+32g/mol+16g/mol$

Molar mass of $C_2H_6SO$ = 78 g/mol

Now we have to calculate the specific heat of this substance.

Specific heat of this substance = $\frac{\text{Molar heat capacity of a compound}}{\text{Molar mass of }C_2H_6SO}$

Specific heat of this substance = $\frac{88.0J/mol.K}{78g/mol}$

Specific heat of this substance = 1.13 J/g.K

Thus, the specific heat of this substance is, 1.13 J/g.K

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3 years ago

It is known that 32g of oxygen takes up 24 litres of space at 25oC. Calculate the volume of oxygen that is needed to react compl

Gwar [14]

6 L of oxygen (O₂)

Explanation:

We have the following chemical reaction:

2 Mg + O₂ → 2 MgO

Now we calculate the number of moles of magnesium:

number of moles = mass / molar weight

number of moles of Mg = 12 / 24 = 0.5 moles

Taking in account the chemical reaction we devise the following reasoning:

if 2 moles of Mg react with 1 mole of O₂

then 0.5 moles of Mg react with X moles of O₂

X = (0.5 × 1) / 2 = 0.25 mole of O₂

mass = number of moles × molar weight

mass of O₂ = 0.25 × 32 = 8 g

Knowing the information given by the problem that 32 g of O₂ takes up 24 liters of space, we devise the following reasoning:

if 32 g of O₂ takes up 24 liters of space

then 8 g of O₂ takes up Y liters of space

Y = (8 × 24) / 32 = 6 L of O₂

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balancing chemical reactions

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Explain why atomic radius decreases as you move to the right across a period for main-group elements but not for transition elem

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3 years ago