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2 answers:
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Answer:
15.4 g
Explanation:
The reaction that takes place is:
- 2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O
First we <u>convert 5 grams of C₅H₁₀ into moles</u>, using its <em>molar mass</em>:
- 5 g ÷ 70 g/mol = 0.07 mol C₅H₁₀
Then we <u>convert C₅H₁₀ moles into CO₂ moles</u>, using the <em>stoichiometric coefficients</em> of the reaction:
- 0.07 mol C₅H₁₀ *
= 0.35 mol CO₂
Finally we <u>convert 0.35 moles of CO₂ into grams</u>:
- 0.35 mol CO₂ * 44 g/mol = 15.4 g
The reaction is shown below,
Step 1: Hydration of Alkene:
In first step Ethene is hydrated to Ethanol through Hydroboration Reaction.
Step 2: Oxidation of Primary Alcohol:
In this step partial oxidation of ethanol is carried out using mild Oxidizing agent <span>Pyridinium chlorochromate (PCC) and Acetaldehyde is produced.
Step 3: Reduction of Acetaldehyde followed by Oxidation:
In this step, first acetaldehyde is reduced to secondary alcohol using grignard reagent. After that the sec. alcohol is oxidized to ketone by using oxidizing agent CrO</span>₃.
Step 1: Hydration of Alkene:
In first step Ethene is hydrated to Ethanol through Hydroboration Reaction.
Step 2: Oxidation of Primary Alcohol:
In this step partial oxidation of ethanol is carried out using mild Oxidizing agent <span>Pyridinium chlorochromate (PCC) and Acetaldehyde is produced.
Step 3: Reduction of Acetaldehyde followed by Oxidation:
In this step, first acetaldehyde is reduced to secondary alcohol using grignard reagent. After that the sec. alcohol is oxidized to ketone by using oxidizing agent CrO</span>₃.