Answer:
The empirical formula is the simplest form;
Given:
Oxygen O at 94.1% and
H at 5.9%
Assume 100grams.
94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O
5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H
There is one mole of O for each mole of H so the empirical formula is 
and written as OH.
The flotation process used in metallurgy involves the separation of gangue from ore.
<h3>How does the flotation process work?</h3>
The various wettability qualities of a material's surface are the foundation of flotation operations. The basic principles of flotation are quite similar to those of a sink and float process, where the materials' relative densities to the medium in which they are deposited determine the basis of the separation.
<h3>What is the process of separating minerals from gangue known as?</h3>
Mineral processing, mineral dressing, or ore dressing are all terms for the process of separating minerals from gangue. It is an important and frequently necessary part of mining. Depending on the type of minerals used, the process may be difficult.
Learn more about minerals here:-
brainly.com/question/26705337
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Answer:
8.33 moles CO2 X. 25mol O2. 16mol CO2. = 13.0 moles
Answer: The answer is Z only
I’m assuming the answer choices are
1) x only
2) Z only - the answer
3) X and Y
4) X and Z
Explanation:
Answer:
I think this is probably the answer you are looking for.
Explanation:
https://youtu.be/PY431ZC5uDc
