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Musya8 [376]
3 years ago
5

Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.

Chemistry
1 answer:
RideAnS [48]3 years ago
3 0

Answer: D=8.27 g/cm³

Explanation:

Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.

D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}

With this equation, the m³ and kg cancel out, and we are left with g/cm³.

D=8.27 g/cm³

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What happens when the vapor pressure of a liquid is equal to the external pressure? The liquid freezes The intermolecular forces
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Answer:

The liquid boils.

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For a liquid, it is the pressure of the Vapor gathering at the top of the surface of the liquid.

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6 0
3 years ago
Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
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<u>Answer:</u> The amount of silver produced in the given reaction is 459.63 g.

<u>Explanation:</u>

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of atoms.

For the given chemical equation:

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver.

This means that, 6.022\times 10^{23} number of atoms of copper produces 2\times 6.022\times 10^{23} number of atoms of silver.

So, 12.83\times 10^{23} number of atoms of copper will produce = \frac{2\times 6.022\times 10^{23}}\times 12.83\times 10^{23}=25.66\times 10^{23} number of atoms of silver.

We know that:

Mass of 1 mole of silver = 107.87 g

Using mole concept:

If, 6.022\times 10^{23} number of atoms occupies 107.87 grams of silver atom.

So, 25.66\times 10^{23} number of atoms will occupy = \frac{107.87g}{6.022\times 10^{23}}\times 25.66\times 10^{23}=459.63g

Hence, the amount of silver produced in the given reaction is 459.63 g.

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