Answer:
The answer to your question is: letter D.
Explanation:
Noble gases are located in group VIIIA of the periodic table, this means that they have 8 eight electrons in their outermost shell.
Due to this characteristic, they are stable and do not react with other elements.
a. 1s22s22p4 The outermost shell of this electron configuration has 6 electrons, then this element has 6 electrons not 8. This configuration is of an element of the group VIA.
b. [Ne]2s22p2 The outermost shell of this element has 4 electrons, so this is not the configuration of a noble gas.
c. [Ar] 3s1 This element only has one electron in its outermost shell, so this is the electron configuration of an alkaline metal.
d. 1s22s22p6 This element has 8 electrons in its outermost shell, so this is the electron configuration of a noble gas.
solution:
First we calculate the number of mole of gas as follows:
PV = n RT
Here temperature; T= 100°C or 373 K
n = PV/ RT
= 4.78 atm * 3.82 L / 0.0821 L ∙ atm / mol ∙ K * 373 K
= 0.596 Moles
Now determine the molar mass of gas as follows:
Number of moles = amount in g/ molar mass
Molar mass = 19.08 grams / 0.596 Moles
= 32.013 g/ mole
This the molar mass of O2 hence the gas is oxygen
Na₂CO₃(s) → 2Na⁺(aq) + CO₃²⁻(aq)
The sodium carbonate formed from a strong base and a weak acid. Hydrolysis is subjected to the anion of a weak acid.
CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻
HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
pH>7 alkaline solution
2Na⁺ + CO₃²⁻ + 2H₂O ⇄ 2Na⁺ + 2OH⁻ + H₂CO₃
Answer:
164atm
Explanation:
Given parameters:
Initial pressure = 150atm
Initial temperature = 27°C = 27 + 273 = 300K
New temperature = 55°C = 328K
Unknown:
New pressure = ?
Solution:
At constant volume, the pressure of a given gas varies directly with the absolute temperature.
Mathematically;
=
P and T are pressure and temperature values
1 and 2 are the initial and new states
Insert the parameters and solve;
=
300P₂ = 150 x 328
P₂ = 164atm
Answer:
How to Formulate an Effective Research Hypothesis
State the problem that you are trying to solve. Make sure that the hypothesis clearly defines the topic and the focus of the experiment.
Try to write the hypothesis as an if-then statement. ...
Define the variables.
Explanation: