___
Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
Elements form bonds to increase their stability. The main types of bonds are:
- Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
- Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
- Covalent bonds: they are formed between nonmetals, which share electrons.
Regarding the bonds in FesO₄:
- Fe is a metal and S a nonmetal, thus they will form ionic bonds.
- S and O are both nonmetals, thus they will form covalent bonds.
Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
Learn more: brainly.com/question/23882847
<h3>
Answer:</h3>
1031.4 Calories.
<h3>
Explanation:</h3>
We are given;
Mass of the copper metal = 50.0 g
Initial temperature = 21.0 °C
Final temperature, = 75°C
Change in temperature = 54°C
Specific heat capacity of copper = 0.382 Cal/g°C
We are required to calculate the amount of heat in calories required to raise the temperature of the copper metal;
Quantity of heat is given by the formula,
Q = Mass × specific heat capacity × change in temperature
= 50.0 g × 0.382 Cal/g°C × 54 °C
= 1031.4 Calories
Thus, the amount of heat energy required is 1031.4 Calories.
Answer:
The solution in beaker A is unsaturated
The solution in beaker B is saturated
Explanation:
A saturated solution is a solution that contains just as much solute as it can normally hold at a particular temperature. An unsaturated solution is a solution that contains less solute than it can normally hold at a particular temperature.
If more solute is added to a saturated solution, the added solute does not dissolve completely. However, if more solute is added to an unsaturated solution, the added solute dissolves.
First, you need to count copper mass in alloy.
Second, you have to make an equation an find x ( the copper mass must be added). The answer is: 13,5g pure copper
First find the mass
44.1 ml @ 1.55 g/mL = 68.355 grams of Ca
the equation
Ca + O2 → CaO
= 55 grams of O2
