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Yuliya22 [10]
2 years ago
9

Dec

Chemistry
1 answer:
scZoUnD [109]2 years ago
6 0

Answer:the pic

Explanation:

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Cells can use the glucose directly, without breaking it down, to carry out cellular processes. True or False?
Akimi4 [234]

Answer:

False

Explanation:

Glucose is a substrate which undergoes various chemical reactions in the mitochondria to produce ATP, which is the universal energy carrier.

6 0
2 years ago
Which line provides an example of an antagonist? (6 points) Jessica gave me an evil glare and an unspoken promise to make my lif
igomit [66]
The sentence "Jessica gave me an evil glare and an unspoken promise to make my life miserable." is the antagonist quote as she is a villain.

7 0
3 years ago
Read 2 more answers
How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?
Tom [10]
The answer is:  " 56 g CaCl₂ " .
__________________________________________________________

Explanation:
__________________________________________________________
2.0 M CaCl₂  = 2.0 mol CaCl₂ / L  ; 

Since: "M" = "Molarity" (measurement of concentration); 

                  = moles of solute per L {"Liter"} of solution.
__________________________________________________________
Note the exact conversion:  1000 mL = 1 L . 

Given: 250 mL ;   

250 mL = ?  L  ?  ;  


250 mL * (1 L / 1000 L) =  (250/1000) L = 0.25 L . 
___________________________________________________________
 
(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol  = 0.50 mol CaCl₂ ;

We have: 0.50 mol CaCl₂ ;  Convert to "g" (grams):

→ 0.50 mol CaCl₂  .
___________________________________________________________
1 mol CaCl₂ = ? g ?

From the Periodic Table of Elements:

1 mol Ca = 40.08 g

1 mol Cl  =  <span>35.45 g .
</span>
There are 2 atoms of Cl in " CaCl₂ " ;  

→ Note the subscript, "2", in the " Cl₂ " ; 
__________________________________________________________
So, to calculate the molar mass of "CaCl₂" :

40.08 g  +  2(35.45 g) = 

40.08 g  +  70.90 g = 110.98 g ;  round to 4 significant figures; 

                                 → round to 111 g/mol .
__________________________________________________________
So:

→  0.50 mol CaCl₂  = ? g CaCl₂  ? ; 

→  0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;

                                             = (0.50) * (111 g) CaCl₂ ;

                                             =  55.5 g CaCl₂  ;

                                                → round to 2 significant figures; 

                                                →  56 g CaCl₂ .
___________________________________________________________
The answer is:  " 56 g CaCl₂ " .
___________________________________________________________
6 0
3 years ago
Read 2 more answers
How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?
slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between  reaction between calcium chloride and aluminum oxide is given as,

3CaCl_{2} (aq)+Al_{2} O_{3} (s) → 3CaO_{2} (s)+2Al Cl_{3} (aq)

The molar ratio of above reaction is  3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with  5. 99 moles of  aluminum oxide  = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

learn more about calcium chloride

brainly.com/question/15296925

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6 0
1 year ago
Convert 0.54 km to dm
Kaylis [27]

.54 km to dm is 5,400 decimeters. Hope this helps, have a BLESSED day! :-)

6 0
2 years ago
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