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ahrayia [7]
3 years ago
6

ii. Use the solubility table to label the state symbols of each compound in the reaction. (1 point) AgNO3 + KCL = AgCl + KNO3

Chemistry
1 answer:
rjkz [21]3 years ago
4 0

Answer:

  • AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)

Explanation:

In a <em>solubility table</em> you find:

  • AgNO₃ (silver nitrate) is highly soluble
  • KCl (potassium chloride) is soluble
  • AgCl (silver chloride) is insoluble
  • KNO₃ (potassium nitrate) is soluble

In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.

Then, the reaction showing the states of the reactants and products is:

  • AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
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Answer:

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2 years ago
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A compound contains sulfur, oxygen, and chlorine. Analysis shows that it contains by mass 26.95% sulfur and 59.61% chlorine. Wha
sladkih [1.3K]

Answer:

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Explanation:

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S: 26.95/32.07 = 0.8403

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Lead (ll) nitride+ammonium sulfate &gt; lead(ll) sulfate + ammonium nitride
Alenkinab [10]

Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

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Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: Pb_3N_2.

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

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Let's write the balanced equation:

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