1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
notsponge [240]
3 years ago
8

Which one of the following statements is FALSE? a In a neutralization reaction, an acid reacts with base to produce a salt and H

2O. b Spectator ions" appear in the total ionic equation for a reaction, but not in the net ionic equation c HF, HCl, and HNO3 are all examples of strong acids. d Titration is a process which can be used to determine the concentration of a solution. e For the reaction of a strong acid with a strong soluble base, the net ionic equation is always H+ + OH- --> H2O
Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

HF is a weak acid and not a strong acid. This is because fluorine is a highly electronegative atom and when it combines with a hydrogen atom then it will attract the valence electron of hydrogen atom more towards itself.

As a result, it will not dissociates easily to give hydrogen ion. Hence, it acts as a weak acid.

A neutralization reaction is defined as a reaction in which an acid reacts with a base to give salt and water. For example, HCl + NaOH \rightarrow NaCl + H_{2}O

It is true that, spectator ions "appear in the total ionic equation for a reaction, but not in the net ionic equation".

Titration is defined as a process in which concentration of an unknown solution is determined using a solution of known concentration.

Thus, we can conclude that the statement HF, HCl, and HNO3 are all examples of strong acids, is false.

You might be interested in
Question 10 OT 20
Airida [17]

Answer:

B) is reduced.

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced and it is oxidizing agent.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized and it is reducing gent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

8 0
3 years ago
IUPAC NAME FOR:<br>CH2(OH)-CH2-CH(C2H5)-OH
fgiga [73]

The IUPAC name for the organic compound CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

This compound above belong to class of organic compound called the alkanols

<h3>What are organic compounds?</h3>

Organic compounds are compounds which contains carbon and hydrogen only.

Some few classes of organic compounds includes the following:

  • Alkanes
  • Alkenes
  • Alkynes
  • Alkanols
  • Alkanals
  • Alkanones
  • Esters
  • Ketones and other

So therefore, the IUPAC name for the organic compound is CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

Learn more about organic compounds:

brainly.com/question/704297

#SPJ1

6 0
2 years ago
I need help with this question
KiRa [710]
A challenge they could face is that the plants are not used to the climate in the new area . (sorry if it’s wrong)
5 0
3 years ago
ANSWER IT PLEASE!!!!! A virus is a genome, or set of chromosomes, contained inside a protein capsule called a capsid. A virus ca
ikadub [295]

Answer:

?

Explanation:

What are the statements? You've given the passage but not the statements

6 0
3 years ago
A second-order reaction has a rate law: rate = k[a]2, where k = 0.150 m−1s−1. If the initial concentration of a is 0.250 m, what
Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s

To determine:

Concentration at time t = 300 s i.e. [a]_{t}

Calculations:

The second order rate equation is:

1/[a]_{t} = kt +1/[a]

substituting for k,t and [a] we get:

1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M

1/[a]t = 49 M-1

[a]t = 1/49 M-1 = 0.0204 M

Hence the concentration of 'a' after t = 5min is 0.020 M



7 0
3 years ago
Other questions:
  • The molar madd of Ca(OH)2
    11·1 answer
  • Sodium - Reacts vigorously with water.
    6·2 answers
  • PLEASE HELP ME ASAPPPPP<br> How many moles are in 10.25 grams of NH3?
    7·1 answer
  • Which answer below correctly identifies the type of change and the explanation for the boiling of water? physical change because
    10·2 answers
  • Calculate the amount of heat energy required to evaporate 27.5 g of water at 100.0°C. (molar heat of vaporization of liquid wate
    11·1 answer
  • The products in a decomposition reaction _____. are compounds can be elements or compounds are elements include an element and a
    10·1 answer
  • Which Earth motion describes the wobbling of the Earth around its precessional axis and
    12·1 answer
  • Formular for solubility​
    5·2 answers
  • Building Vocabulary
    9·1 answer
  • A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!