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notsponge [240]
3 years ago
8

Which one of the following statements is FALSE? a In a neutralization reaction, an acid reacts with base to produce a salt and H

2O. b Spectator ions" appear in the total ionic equation for a reaction, but not in the net ionic equation c HF, HCl, and HNO3 are all examples of strong acids. d Titration is a process which can be used to determine the concentration of a solution. e For the reaction of a strong acid with a strong soluble base, the net ionic equation is always H+ + OH- --> H2O
Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

HF is a weak acid and not a strong acid. This is because fluorine is a highly electronegative atom and when it combines with a hydrogen atom then it will attract the valence electron of hydrogen atom more towards itself.

As a result, it will not dissociates easily to give hydrogen ion. Hence, it acts as a weak acid.

A neutralization reaction is defined as a reaction in which an acid reacts with a base to give salt and water. For example, HCl + NaOH \rightarrow NaCl + H_{2}O

It is true that, spectator ions "appear in the total ionic equation for a reaction, but not in the net ionic equation".

Titration is defined as a process in which concentration of an unknown solution is determined using a solution of known concentration.

Thus, we can conclude that the statement HF, HCl, and HNO3 are all examples of strong acids, is false.

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The time required to reduce the concentration from 0.00757 M to 0.00180 M is equal to 1.52 × 10⁻⁴ s. The half-life period of the reaction is 9.98× 10⁻⁵s.

<h3>What is the rate of reaction?</h3>

The rate of reaction is described as the speed at which reactants are converted into products. A catalyst increases the rate of the reaction without going under any change in the chemical reaction.

Given the initial concentration of the reactant, C₀= 0.00757 M

The concentration of reactant after time t is C₁= 0.00180 M

The rate constant of the reaction, k = 37.9 M⁻¹s⁻¹

For the first-order reaction: C_t =C_0-kt

0.00180 = 0.00757 - (37.9) t

t =  1.52 × 10⁻⁴ s

The half-life period of the reaction: t_{\frac{1}{2} } =\frac{C_0}{2k}

t_{\frac{1}{2} } =\frac{0.00757}{2\times 37.9}

Half-life of the reaction = 9.98 × 10⁻⁵s

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The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles

<h3>Balanced equation </h3>

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From the balanced equation above,

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<h3>How to determine the mole of oxygen needed </h3>

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