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2 years ago

Why is ba(cn)2 soluble

Chemistry

1 answer:

amid [387]2 years ago

5 0

Answer:

Barium Cyanide, Ba(CN)2, is formed by passing anhydrous hydrocyanic acid over cooled barium hydroxide crystals, and dissolves in the water of crystallisation of the hydrated baryta. With anhydrous barium oxide or hydroxide too vigorous a reaction takes place and the cyanide is decomposed.

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Two containers, one with a volume of 3.0 L and the other with a volume of 2.0 L contain, respectively, argon gas at 1.1 atm and

aalyn [17]

Answer:

a. $p_T=0.93atm$ .

$p_{Ar}=0.66atm\\\\p_{He}=0.3atm$

$x_{Ar}=0.6875\\\\x_{He}=0.3125$

Explanation:

Hello,

In this case, considering that the valve is opened, we can use the Boyle's law in order to compute the final pressure of argon by considering its initial pressure and volume and a final volume of 5.0 L:

$p_{Ar}=\frac{1.1atm*3.0L}{5.0L}=0.66atm$

And the final pressure of helium:

$p_{He}=\frac{0.75atm*2.0L}{5.0L}=0.3atm$

Which actually are the partial pressure of both of them, it means that the total pressure is:

Finally, the mole fraction of each gas is computed by considering the Dalton's law:

$x_i=\frac{p_i}{p_T}$

$x_{Ar}=\frac{0.66atm}{0.93atm} =0.6875\\\\x_{He}=\frac{0.3atm}{0.93atm} =0.3125$

Best regards.

6 0

3 years ago

When heat is added to the substances, the atoms being to?

uranmaximum [27]

Answer:

atoms move faster

Explanation:

Space is produced when substances are heated. The atoms became extremely energetic and began to move much quicker than usual. When this happens, energy is released in the form of heat, light, and so on. As a result, kinetic energy rises and atoms collide more frequently.

3 0

1 year ago

An electron in a hydrogen atom relaxes to the n=4 level, emitting light of 74 THz.

Solnce55 [7]

Delta E = Ef - Ei
E = energy , h = plank constant , v = frequency
h= 6.626 * 10 ^-34 j*s , T = 10 ^ 12 , v = 74 * 10 ^12 Hz , Hz = s^-1

E = ( 6.626 * 10^ -34 j*s) ( 74 * 10 ^ 12 s^ -1 ) = 4.90 * 10 ^ -20 J
Delta E = Ef - Ei
-4.90 * 10 ^ -20 J = -2.18 * 10 ^ -18J ( 1/4 ^2 - 1/x ^2)
0.0225 = 0.0625 - ( 1/x ^ 2)
0.225 - 0.0625 = - 1/ x ^ 2

- 0.0400 = - 1/x ^2 = -1 / - 0.0400 = x^2
25 = x^2
x = 5

6 0

3 years ago

What might be useful for adding solids to a tube

vagabundo [1.1K]

C funnel because the funnel would have a large enough entrance to put a solid through

7 0

3 years ago

Acetic acid has a pKa of 4.74. Buffer A: 0.10 M HC2H3O2, 0.10 M NaC2H3O2 Buffer B: 0.30 M HC2H3O2, 0.30 M NaC2H3O2 Buffer C: 0.5

e-lub [12.9K]

Answer:

Buffer B has the highest buffer capacity.

Buffer C has the lowest buffer capacity.

Explanation:

An effective weak acid-conjugate base buffer should have pH equal to $pK_{a}$ of the weak acid. For buffers with the same pH, higher the concentrations of the components in a buffer, higher will the buffer capacity.

Acetic acid is a weak acid and $CH_{3}COO^{-}$ is the conjugate base So, all the given buffers are weak acid-conjugate base buffers. The pH of these buffers are expressed as (Henderson-Hasselbalch):

$pH=pK_{a}(CH_{3}COOH)+log\frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}$

$pK_{a}(CH_{3}COOH)=4.74$

Buffer A: $pH=4.74+log(\frac{0.10}{0.10})=4.74$

Buffer B: $pH=4.74+log(\frac{0.30}{0.30})=4.74$

Buffer C: $pH=4.74+log(\frac{0.10}{0.50})=4.04$

So, both buffer A and buffer B has same pH value which is also equal to $pK_{a}$ . Buffer B has higher concentrations of the components as compared to buffer A, Hence, buffer B has the highest buffer capacity.

The pH of buffer C is far away from $pK_{a}$ . Therefore, buffer C has the lowest buffer capacity.

6 0

2 years ago