Answer:
14) The edge dislocation is more plastic than the screw dislocation
15) So as to form kinks that are fast moving
Explanation:
14) Edge and screw dislocations are the two main types of mobile dislocations
The three dimensional core of the screw dislocation prevents the slipping of the layers (one over the other) in a BCC metal such that kinks are required to be formed first by thermal activation (heating) in order. The kinks are edge dislocation that move such that the screw dislocation moves forward
Hence, the edge dislocation is more plastic than the screw dislocation
15) The three dimensional structure of a screw dislocation acts like a wedge which resists the slipping of the layers in the BCC structure such that the screw dislocation needs to be highly thermally activated forming kinks before the surrounding layers can move.
Answer:
The correct answer would be the third choice.
Homo-genesis mixtures are the same in composure, and will be hard to break apart other then with chemical means.
Hope this helps!
Explanation:
An acid is a substance that produces excess hydroxonium ions in solution.
An acid based on the pH scale is a substance that has a low pH. Acid lies within a range of 1-7 on the pH scale.
- A pH of 7 is for neutral compounds like water.
- A pH greater that 7 is for basic compounds.
- In order to raise the pH, we are driving at a substance becoming more neutral or basic.
This can be achieved by adding more base to the solution of the substance. When we add more base, hydroxyl ions will neutralize the excess hydroxonium ions and drag the pH towards that of neutrality.
Addition of more base can eventually make the substance basic.
learn more:
Phosphoric acid brainly.com/question/11062486
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Answer: beta, gamma, alpha
Explanation: Beta is weakest gamma is middle alpha is strongest
You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.
You can use a modified dilution formula to calculate the volume of 30 % sugar.
<em>V</em>_1×<em>C</em>_1 + <em>V</em>_2×<em>C</em>_2 = <em>V</em>_3×<em>C</em>_3
Let the volume of 30 % sugar = <em>x</em> pt. Then the volume of the final 20 % sugar = (5 + <em>x</em> ) pt
(<em>x</em> pt×30 % sugar) + (5 pt×5 % sugar) = (<em>x</em> + 5) pt × 20 % sugar
30<em>x</em> + 25 = 20x + 100
10<em>x</em> = 75
<em>x</em> = 75/10 = 7.5
