Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m
1 answer:
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Answer:
(a) The rate of disappearance of is:
M/s
(b) The value of rate constant is: 0.83036
(c) The units of rate constant is:
(d) The rate will increase by a factor of 3.24
Explanation:
The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.
For the given reaction:
rate = =
=
-----(1)
According to the question, the reaction is second order in NO and first order in .
Then we can say that, rate = k -----(2)
where k is the rate constant.
The rate of disappearance of NO is given:
=
M/s.
(a) From (1), we can get the rate of disappearance of .
Rate of disappearance of =
= (0.5)*(
) M/s =
M/s.
(b) The rate of the reaction can be obtained from (1).
rate = = (0.5)*(
)
rate = M/s
The value of rate constant can be obtained by using (2).
rate constant = k =
k = = 0.83036
(c) The units of the rate constant can be obtained from (2).
k =
Substituting the units of rate as M/s and concentrations as M, we get:
=
(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.
If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of = 3.24
Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series
Explanation:
Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.
Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.
In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .
Thus for mass number : 235 = 207+4X
4X= 28
X = 7
Thus for atomic number : 92 = 82+2X-Y
2X- Y = 10
2(7) - Y= 10
14-10 = Y
Y= 4
Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series