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2 years ago

The molar solubility for baco3 is 9.0 x 10-5 m at 25 degrees

Chemistry

1 answer:

Ierofanga [76]2 years ago

8 0

Ksp = [Ba2+][CO32-] = (9.0 X 10⁻⁵)² = 8.1 X 10⁻⁹

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Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.

Drupady [299]

Answer:

Honestly have no clue

Explanation:

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3 years ago

How much heat is released when 105 g of steam at 100.0°C is cooled to ice at -15.0°C? The enthalpy of vaporization of water is 4

vitfil [10]

Answer:

MgCal2=Cal2

Explanation:

5 0

2 years ago

Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following

bearhunter [10]

Answer:

$210.7~g~MgCO_3$

Explanation:

We have to start with the reaction:

$MgCO_3~->~MgO~+~CO_2$

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

$(12*1)+(16*2)=44~g/mol$

In other words: $1~mol~CO_2=~44~g~CO_2$ . With this in mind, we can calculate the moles:

$110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2$

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

$2.5~mol~CO_2=2.5~mol~MgCO_3$

With the molar mass of $MgCO_3$ ( $(23.3*1)+(12*1)+(16*3)=84.3~g/mol$ . With this in mind, we can calculate the grams of magnesium carbonate:

$2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3$

I hope it helps!

8 0

2 years ago

The structural level of a protein least affected by a disruption in hydrogen bonding is the

sergeinik [125]

I think the correct answer from the choices listed above is option A. The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level. The other levels are very much affected by hydrogen bonding. Hope this answers the question.

7 0

3 years ago

How many ATOMS of OXYGEN are there in the following compound

STatiana [176]

6 Atoms!
Mg = 1 atom.
O = 4 atoms.
A = 1 atom.

5 0

2 years ago