Answer:
m = T/10 = (1/10) T
Explanation:
From the question given:
∑F = ma .... (1)
∑F = T – 10m .... (2)
a = 0 m/s²
m =?
Thus, we can obtain m in terms of T as shown below:
From equation (1)
∑F = ma
a = 0 m/s²
∑F = ma = m × 0
∑F = 0
Next, substitute the value of ∑F into equation (2) to obtain m. This is illustrated below:
∑F = T – 10m
∑F = 0
0 = T – 10m
Rearrange
0 + 10m = T
10m = T
Divide both side by 10
m = T/10
m = (1/10) T
Therefore, m is (1/10) T
Answer:
Explanation:
vertical magnetic field B_v = 4 x 10⁻⁵ T.
Magnetic field due to horizontal current at point 20 cm above
= (μ₀/4π ) x (2i / R)
= 10⁻⁷ x 2 x 20/ 20 x 10⁻²
= 2 x 10⁻⁵ T
It will act coming out of paper. Hence it will be normal to magnetic field given .
So resultant magnetic field
= √ (4² + 2²) x 10⁻⁵ T
= 4.47 X 10⁻⁵ T .
A positive charged atom has lost electrons.
Electrons are present in the outer shell of an atom, loosely bond to the nucleus, the only binding force on the electrons is the electric force, while the protons are inside the nucleus, and tightly bond to the nucleus by nucleus binding force, therefore an atom can only be positively charged when it loose electron from the shall.
Answer:
The speed of the boxes are 1 m/s.
Explanation:
Given that,
Mass of box = 1 kg
Mass of another box = 2 kg
Suppose 1 kg box moves with 3 m/s speed.
We need to calculate the speed of the boxes
Using formula of conservation of momentum
Where, u = initial velocity
v = final velocity
Put the value into the formula
Hence, The speed of the boxes are 1 m/s.