Answer:
220 A
Explanation:
The magnetic force on the floating rod due to the rod held close to the ground is F = BI₁L where B = magnetic field due to rod held close the ground = μ₀I₂/2πd where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, I₂ = current in rod close to ground and d = distance between both rods = 11 mm = 0.011 m. Also, I₁ = current in floating rod and L = length of rod = 1.1 m.
So, F = BI₁L
F = (μ₀I₂/2πd)I₁L
F = μ₀I₁I₂L/2πd
Given that the current in the rods are the same, I₁ = I₂ = I
So,
F = μ₀I²L/2πd
Now, the magnetic force on the floating rod equals its weight , W = mg where m = mass of rod = 0.10kg and g = acceleration due to gravity = 9.8 m/s²
So, F = W
μ₀I²L/2πd = mg
making I subject of the formula, we have
I² = 2πdmg/μ₀L
I = √(2πdmg/μ₀L)
substituting the values of the variables into the equation, we have
I = √(2π × 0.011 m × 0.1 kg × 9.8 m/s²/[4π × 10⁻⁷ H/m × 1.1 m])
I = √(0.01078 kgm²/s²/[2 × 10⁻⁷ H/m × 1.1 m])
I = √(0.01078 kgm²/s²/[2.2 × 10⁻⁷ H])
I = √(0.0049 × 10⁷kgm²/s²H)
I = √(0.049 × 10⁶kgm²/s²H)
I = 0.22 × 10³ A
I = 220 A
Reduce friction because friction just makes things harder
Answer:

Explanation:
The x- and y- components of the velocity vector can be written as following:


Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:

Answer:
<h2>Stunt car A and stunt car B are identical cars with the same mass of 35.9 kg. They are both traveling at 37.1 m/s. Stunt car A crashes into a hard concrete wall, whereas stunt car B crashes into a big soft mattress. They both come to a complete stop after the impact.Stunt Car A experiences a <u>LARGE FORCE</u> over a <u>SHORT PERIOD</u> of time. Stunt Car B experiences a <u>SMALL FORCE</u> over a <u>LONG PERIOD</u> of time. Because of the force experienced by Stunt Car A, it will sustain <u>MORE</u> damage than Stunt Car B.</h2>
Explanation:
As we know that force is given as rate of change in momentum
so it is defined as

so here we know that both the cars are identical and both are moving with same speed so after coming to rest both the cars have same change in momentum
while Car A will experience more force because due to collision with concrete wall the time of collision is very small as compared to Car B
So Force on Car A is more than the force on Car B