Answer:
The magnetic field strength due to current flowing in the wire is9.322 x 10⁻⁶ T.
Explanation:
Given;
electric current, I = 21.3 A
distance of the magnetic field from the wire, R = 45.7 cm = 0.457 m
The strength of the resulting magnetic field at the given distance is calculated as;

Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

Therefore, the magnetic field strength due to current flowing in the wire is 9.322 x 10⁻⁶ T.
<span>In this case we are given a force of 29,000 N. We know
that the equation we can use is:</span>
Force = mass * acceleration
However this is not just any type of force, because this
is the weight of the elevator. So when the force is equal to weight, the
acceleration acting is simply gravity. Therefore:
weight = mass * gravity
Calculating for mass:
mass = 29,000 N / (9.8 m/s^2)
<span>mass = 2,959.18 kg</span>