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3 years ago

In a chemical reaction, mass is conserved. this means that...

1 answer:

8 0

Atoms are the smallest particales of an element that can take part in a chemical reaction. During a chemical reaction no particles are created or destroyed. The atoms are simply rearranged from the reactants to the products, mass is NEVER lost or gained in chemical reactions...Mass is ALWAYS conserved. :) Hope this helped

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I will give brainliest!!! In the reaction represented by the equation Al2O3 -> Al + O2, what is the mole ratio of aluminum to

Effectus [21]

Answer:;

4:3

Explanation:

Balanced:

4Al + 302 yields 2al2O3

7 0

3 years ago

What is the gram formula mass of Ca3(PO4)2

Georgia [21]

Mass Molar of $Ca_{3} (PO_4)_2$
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
--------------------------------------
Mass Molar of $Ca_{3} (PO_4)_2$ = 120 + 62 + 128 = 310 g/mol

Therefore: What is the gram formula mass of Ca3(PO4)2 ?
Answer: 310 grams

6 0

3 years ago

What is the formula for energy change?

rewona [7]

Answer:

Below:

Explanation:

To calculate an energy change for a reaction: add together the bond energies for all the bonds in the reactants - this is the 'energy in' add together the bond energies for all the bonds in the products - this is the 'energy out.

Hope it helps....

It's Muska

5 0

2 years ago

The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?

Agata [3.3K]

Answer: The molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

Explanation:

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$PbI_2\rightleftharpoons Pb^{2+}+2I^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Pb^{2+}][I^-]^2$

We are given:

$K_{sp}=7.9\times 10^{-9}$

Putting values in above equation, we get:

$7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L$

Hence, the molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

3 0

3 years ago

How many hydrogen atoms are in 5.20 mol of ammonium sulfide?

Fofino [41]

1) Molecular formula of ammonium sulfide

(NH4)2 S

2) That means that there are 2*4 = 8 atoms of hydrogen in each molecule of ammoium sulfide, so in 5.20 mol of molecules will be 8 * 5.20 mol = 41.6 moles of atoms of hydrogen

3) To pass to number of atoms multiply by Avogadro's number: 6.022 * 10^23

41.6 moles * 6.022 * 10^23 atoms / mol = 250.5 * 10^23 = 2.50 * 10^25 atoms

Answer: 2.50 * 10^25

8 0

3 years ago