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Mama L [17]
3 years ago
11

NOOO LINNKKKSSS

Chemistry
2 answers:
Anvisha [2.4K]3 years ago
8 0
I believe the answer is d :)!
Elena L [17]3 years ago
3 0
The answer is D I hope this helps you !
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The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
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Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

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</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
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