A camera is a motor.
A drill is a motor.
A hand-squeeze flashlight is a generator.
Hope this helped :)
Answer:
4 km/hr
Explanation:
suppose 's' is Diane's speed with no current.
't' represents time in hrs.
Using the formula:
Distance = speed 's' x time 't'
-> when she swims against the current, equation will be,
5= (s-2)t
t= 5/(s-2)
->when she was swimming with the current, equation is,
15= (s+2) t
t= 15/(s+2)
equating eq(1) and (2)
5/(s-2) = 15/(s+2)
5s + 10 = 15s - 30
40= 10s
s= 40/10
s=4
Therefore, if there were no current, her speed is 4km/hr
backward movement
because momentum = mass × speed
And mass must be in positive value..
so negative value is speed
which moving backward..
0.345 m.
<h3>Explanation</h3>
The wavelength is the distance that the wave travels in each cycle. The wave travels 345 meters in each second. Let the wavelength of this wave be
. That's the distance the wave travels in one cycle.
The frequency of the sound wave is 1 000 Hz, meaning that there are 1 000 cycles in each second. The wave travels a distance of 1 000 wavelengths in one second. That would be a distance of
.
From the speed of the wave, the wave travels 345 meters in one second. In other words,
.
.
To generalize:
,
where
wavelength of the wave,
the speed of the wave, and
the frequency of the wave.
The problem is solved and the questions are answered below.
Explanation:
a. To calculate the speed of the 0.66 kg ball just before the collision
V₀ + K₀ = V₁ + K₁
= mgh₀ = 1/2 mv₁²
where, h= r - r cosθ
V = 
V = 2.42 m/s
b. Calculate the speed of the 0.22 kg ball immediately after the collision
y = y₀ + Vy₀t - 1/2 gt²
0 = 1.2 - 1/2 gt²
t = 0.495 s
x = x₀ + Vx₀t
1.4 = 0 + vx₀ (0.495)
Vx₀ = 2.83 m/s
C. To Calculate the speed of the 0.66 kg ball immediately after the collision
m₁ v₁ = m₁ v₃ + m₂ v₄
(0.66)(2.42) = (0.66) v₃ + (0.22)(2.83)
V₃ = 1.48 m/s
D. To Indicate the direction of motion of the 0.66 kg ball immediately after the collision is to the right.
E. To Calculate the height to which the 0.66 kg ball rises after the collision
V₀ + k₀ = V₁ + k₁
1/2 mv₀² = mgh₁
h₁ = v₀²/2 g
= 0.112 m
F. Based on your data, No the collision is not elastic.
Δk = 1/2 m₁v₃² =1/2 m₂v₄² - 1/2 m₁v₁²
= 1/2 (0.66)(1.48)² + 1/2 (0.22)(2.83)² - 1/2 (0.66)(2.42)²
= - 0.329 J
Hence, kinetic energy is not conserved.