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crimeas [40]
2 years ago
8

Suppose you look at a spectrum of visible light by looking through a prism or diffraction grating. How can you decide whether it

is an emission line spectrum or an absorption line spectrum?
Physics
2 answers:
elena55 [62]2 years ago
5 0

Answer:An emission line spectrum consists of bright lines on a dark background, while an absorption line spectrum consists of dark lines on a rainbow background.

Explanation:

ICE Princess25 [194]2 years ago
5 0

Answer:

If you see discrete wavelengths(colors) it is emission line spectrum. However , If you see all visible wavelengths (like rainbow ) it is absorbtion line spectrum.

Explanation:

You might be interested in
A camera, a drill, and a hand-squeeze flashlight use either a generator or a motor as a component. Identify which component each
muminat

A camera is a motor.

A drill is a motor.

A hand-squeeze flashlight is a generator.

Hope this helped :)

4 0
3 years ago
Read 2 more answers
Diane swim 5 kilometers against the current in the same amout of time it took her to swim 15 kilometers with the current . The r
lidiya [134]

Answer:

4 km/hr

Explanation:

suppose 's' is Diane's speed with no current.

't' represents time in hrs.

Using the formula:

Distance = speed 's' x time 't'

-> when she swims against the current, equation will be,

5= (s-2)t

t= 5/(s-2)

->when she was swimming with the current, equation is,

15= (s+2) t

t= 15/(s+2)

equating eq(1) and (2)

5/(s-2) = 15/(s+2)

5s + 10 = 15s - 30

40= 10s

s= 40/10

s=4

Therefore, if there were no current, her speed is 4km/hr

5 0
3 years ago
A car has a momentum of -456 kg*m/s. What direction is it moving?
Solnce55 [7]

backward movement

because momentum = mass × speed

And mass must be in positive value..

so negative value is speed

which moving backward..

6 0
3 years ago
a female vocalist with a soprano voice can sing as high as 1000 hz. given that the speed of sound is 345 m/s what is the wavelen
Neporo4naja [7]

0.345 m.

<h3>Explanation</h3>

The wavelength is the distance that the wave travels in each cycle. The wave travels 345 meters in each second. Let the wavelength of this wave be \lambda. That's the distance the wave travels in one cycle.

The frequency of the sound wave is 1 000 Hz, meaning that there are 1 000 cycles in each second. The wave travels a distance of 1 000 wavelengths in one second. That would be a distance of 1,000\;\lambda.

From the speed of the wave, the wave travels 345 meters in one second. In other words,

1,000\;\lambda = 345.

\lambda = \dfrac{345}{1,000} = 0.345\;\text{m}.

To generalize:

\lambda = \dfrac{v}{f},

where

  • \lambda wavelength of the wave,
  • v the speed of the wave, and
  • f the frequency of the wave.
3 0
3 years ago
The experimental apparatus shown in the figure above contains a pendulum consisting of a 0.66 kg ball attached to a string of le
lara31 [8.8K]

The problem is solved and the questions are answered below.

Explanation:

a. To calculate the speed of the 0.66 kg ball just before the collision

V₀ + K₀ = V₁ + K₁

= mgh₀ = 1/2 mv₁²

where, h= r - r cosθ

V = \sqrt{2gh}

 V = 2.42 m/s

b. Calculate the speed of the 0.22 kg ball immediately after the collision

y = y₀ + Vy₀t - 1/2 gt²

0 = 1.2 - 1/2 gt²

t = 0.495 s

x = x₀ + Vx₀t

1.4 = 0 + vx₀ (0.495)

Vx₀ = 2.83 m/s

C. To Calculate the speed of the 0.66 kg ball immediately after the collision

m₁ v₁ = m₁ v₃ + m₂ v₄

(0.66)(2.42) = (0.66) v₃ + (0.22)(2.83)

V₃ = 1.48 m/s

D. To Indicate the direction of motion of the 0.66 kg ball immediately after the collision is to the right.

E. To Calculate the height to which the 0.66 kg ball rises after the collision

V₀ + k₀ = V₁ + k₁

1/2 mv₀² = mgh₁

h₁ = v₀²/2 g

  = 0.112 m

F. Based on your data, No the collision is not elastic.

Δk = 1/2 m₁v₃² =1/2 m₂v₄² - 1/2 m₁v₁²

     = 1/2 (0.66)(1.48)² + 1/2 (0.22)(2.83)² - 1/2 (0.66)(2.42)²

    = - 0.329 J

Hence, kinetic energy is not conserved.

8 0
2 years ago
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