Vi = Velocity initial = 35 m/s
Vf = Velocity final = 75 m/s
t = 5s
Equation:
Vf = Vi + at
65 = 35 + a(5)
30 = 5a
a = 6
Acceleration was 6 m/s^2
C. 6 m/s^2
Answer:
2.71 m
Explanation:
Force is the product of mass and acceleration
F=m*a
Work done is the product of force and distance
Work done=F*d
In this case;
F= 35 N
Work done = 95 J
95 =35 * d
95 /35 = d
2.71 m= d
Hey there mate ;)
Given PPT image question is attached.
For answers :-
☆ The spectators in the stand are like particles in a <em><u>solid</u></em><em> </em>because <em><u>the</u></em><em><u> </u></em><em><u>spectators</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>sitting</u></em><em><u> </u></em><em><u>very</u></em><em><u> </u></em><em><u>close</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>no</u></em><em><u> </u></em><em><u>spaces</u></em><em><u> </u></em><em><u>in between</u></em><em><u> </u></em><em><u>them</u></em><em><u>,</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>property</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>solids</u></em><em><u>. </u></em>
☆ The players in the pitch are like particles in a <em><u>gas</u></em><em> </em>because <em><u>there</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>large</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u>space</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>players</u></em><em><u>,</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>property</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>gases</u></em><em><u>.</u></em>
☆ The spectators standing in the terraces are like particles in a <em><u>liquid</u></em> because <em><u>there is </u></em><em><u>little</u></em><em><u> space in between the spectators, which is like a property of liquid.</u></em>
Average speed = total distance / total time
total distance = 40 + 20 = 60km
total time taken = 10 + 5 = 15 minutes
Average speed = 60/15 = 4km/min
Answer:
The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.
Explanation:
Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively
and the mass of big rock be 'M'
Initial momentum of the system equals
Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'
Thus the final momentum of the system is
Equating initial and the final momenta we get
Now since the surface is frictionless thus the energy is also conserved thus
Similarly the final energy becomes
\
Equating initial and final energies we get
Solving i and ii we get
Using this in equation i we get
Thus putting v = -v' in equation i we get V' = 0
This implies Smaller stone rebounds while as larger stone remains stationary.