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Alborosie
3 years ago
15

Given the mechanism of C5M action, what is the most likely reason that C5M concentrations greater than 2 µM were NOT used by the

scientists for this experiment?
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

It can cause a significant negative effects on certain tissues and target cells.

Explanation:

Generally, based on the mechanism of C5M, its presence in any experiment can harm certain tissues and target cells. Therefore, the use of a large amount (in terms of concentration above 2 µM) of C5M will enhance the negative effects of C5M on the surrounding/neighboring tissue as well as the normal division of target cells. That is the reason why a higher concentration was not used in the experimental runs.

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An element's atomic number is the​
Zepler [3.9K]

the atomic number of a chemical element (also known as its proton number) is the number of protons found in the nucleus of an atom of that element, and therefore identical to the charge number of the nucleus.

Hope this helped

8 0
3 years ago
Which graph would you use to show the percentage of cookies sold by each
tatuchka [14]

Answer:

You would use a bar graph

4 0
3 years ago
If you are pushing on a box with a force of 20 N and there is a 7 N force on the box due to sliding friction, what is the net fo
vovangra [49]

Answer:

13 N

Explanation:

The Net Force of an object should be the difference between the forces applied to the object if the object is not in equilibrium. This object is not in equilibrium so therefore by finding the difference between the forces, you will find your answer. 20 N - 7 N = 13 N.

6 0
3 years ago
Read 2 more answers
Many Amtrak trains can travel at a top speed of 42.0 m/s. Assuming a train maintains that speed for several hours, how many kilo
777dan777 [17]

Answer:

605 km

Explanation:

Hello

the same units of measure should be used, then

Step 1

convert  42 m/s ⇒   km/h

1 km =1000 m

1 h = 36000 sec

42 \frac{m}{s}*\frac{1\ km}{1000\ m}=0.042\ \frac{km}{s}\\ 0.042\ \frac{km}{s}\\

0.042\ \frac{km}{s}*\frac{3600\ s}{1\ h} =151.2 \frac{km}{h}\\ \\Velocity =151.2\ \frac{km}{h}

Step 2

find kilometers traveled after 4  hours

V=\frac{s}{t}\\ \\

V,velocity

s, distance traveled

t. time

now, isolating s

V=\frac{s}{t} \\s=V * t\\

and replacing

s=V * t\\s=151.2\frac{km}{h}*4 hours\\ s=604.8 km\\

S=604.8 Km

Have a great day

4 0
3 years ago
The express train can travel 100 miles per hour. This information describes the train'sAnsweracceleration.direction.speed.veloci
solmaris [256]
Velocity because it gives the displacement and time
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4 years ago
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