Answer:
a) E = 0
b) 
Explanation:
The electric field for all points outside the spherical shell is given as follows;
a) 
From which we have;
E = 0/A = 0
E = 0
b)
By Gauss theorem, we have;
Therefore, we get;
The electrical field outside the spherical shell
Therefore, we have;
1.potential energy 2.kinetic energy 3.electrical energy 4.electrical energy
The approximate orbital period of this star is 13 years.
<h3>What is Kepler's third law?</h3>
The square of a planet's period of revolution around the sun in an elliptical orbit is directly proportional to the cube of its semi-major axis, states Kepler's law of periods.
T² ∝ a³
The time it takes for one rotation to complete depends on how closely the planet orbits the sun. With the use of the equations for Newton's theories of motion and gravitation, Kepler's third law assumes a more comprehensive shape:
P² = 4π² /[G(M₁+ M₂)] × a³
where M₁ and M₂ are the two circling objects' respective masses in solar masses.
Learn more about Kepler's third law here:
brainly.com/question/1608361
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Answer:
Therefore the escape velocity from Mar's gravity is 
m/s.
Explanation:
Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.
Escape velocity
G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²
M= mass of Mars = 6.42×10²³ kg
R = Radius of the Mars = 3.40×10³m
The escape velocity does not depend on the velocity of a object.
m/s
Therefore the escape velocity from Mar's gravity is m/s.
