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3 years ago

The biggest polluters of The water in the ground are A home owners b farmers C animals or D plant

Chemistry

1 answer:

bekas [8.4K]3 years ago

6 0

Answer:

farmers

Explanation:

They drop too much nutrients, namely ammonia

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Calculate the density of mercury of it pours exactly 22.5 mL into a graduated cylinder and has a mass of 316 g.

Rasek [7]

Density = mass/volume = 316/22.5 = 14.045g/mL.

8 0

3 years ago

Choose the mole ratio below that is INCORRECT based on the given balanced equation:

sdas [7]

Answer:

4 moles CO₂ = 4 moles O₂

Explanation:

The incorrect mole ratio is 4 moles CO₂ = 4 moles O₂.

Let us write the reaction equation:

2C₂H₅OH + 7O₂ → 4CO₂ + 6H₂O

To write mole ratios in a chemical reaction, we must ensure the equation is balanced.

Since the given expression is balanced,

Then 4 moles CO₂ = 4 moles O₂ is not correct;

Rather;

4 moles CO₂ = 7 moles O₂ is the right expression

6 0

3 years ago

A tank contains 200 gallons of water in which 300 grams of salt is dissolved. A brine solution containing 0.4 kilograms of salt

Nadusha1986 [10]

Answer:

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

Explanation:

given amount of salt at time t is A(t)

initial amount of salt =300 gm =0.3kg

=>A(0)=0.3

rate of salt inflow =5*0.4= 2 kg/min

rate of salt out flow =5*A/(200)=A/40

rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow

$dA/dt=2-(A/40)\\\\dA=2dt-(A/40)dt\\\\dA+(A/40)dt=2dt$

integrating factor

$=e^{\int\limits (1/40) \, dt}$

integrating factor $=e^{(1/40)t}$

multiply on both sides by $=e^{(1/40)t}$

$dAe^{(1/40)t}+(A/40)e^{(1/40)t} dt =2e^{(1/40)t}t\\\\(Ae^{(1/40)t})=2e^{(1/40)t}t$

integrate on both sides

$\int\limits(Ae^{(1/40)t})=\int\limits2e^{(1/40)t}dt\\\\(Ae^{(1/40)t})=2*40e^{(1/40)t}+C\\\\A=80+(C/e^{(1/40)t})\\\\A(0)=0.3\\\\0.3=80+(C/e^{(1/40)t}^*^0)\\\\0.3=80+(C/1)\\\\C=0.3-80\\\\C=-79.7\\\\A(t)=80-(79.7/e^{(1/40)t})$

after long period of time means t - > ∞

${t \to \infty}\\\\ \lim_{t \to \infty} A_t \\\\ \lim_{t \to \infty} (80)-(79/{e^{(1/40)t}}\\\\=80-(0)\\\\=80$

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

6 0

3 years ago

2.17 in to 10^23 molecules of Br 2 to moles

KiRa [710]

I don't get what you are saying... Can you reword it?

3 0

3 years ago

Show chemical equation for the reaction of water

cricket20 [7]

Explanation:

2H2(g) + O2(g) → 2H2O(l )

3 0

2 years ago