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8 months ago

Calculate the volume in (L) of 1.13x10^5 grams of liquid sodium which has a density of 0.929g/cm3

Chemistry

1 answer:

Yuki888 [10]8 months ago

8 0

The volume of the liquid sodium is 121.64 L

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the above formula, we can obtain the volume of the liquid. Details below

<h3>How to determine the volume of the sodium liquid</h3>

Mass of liquid = 1.13×10⁵ g
Density of liquid = 0.929 g/cm³
Volume of liquid =?

Density = mass / volume

Thus,

Volume = mass / density

Volume of liquid = 1.13×10⁵ / 0.929

Volume of liquid = 121636.17 cm³

Divide by 1000 to express in liter

Volume of liquid = 121636.17 / 1000

Volume of liquid = 121.64 L

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A sample of a compound contains 3.21 g of sulfur and 11.4 g of fluorine. Which of the following represents the empirical formula

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The empirical formula is SF6 (option E)

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The ph of a solution prepared by mixing 45.0 ml of 0.183 m koh and 35.0 ml of 0.145 m hcl is ________.

Naddika [18.5K]

Answer:

12.6.

Explanation:

We should calculate the no. of millimoles of KOH and HCl:

no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.

no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.

It is clear that the no. of millimoles of KOH is higher than that of HCl:

So,

[OH⁻] = [(no. of millimoles of KOH) - (no. of millimoles of HCl)] / (V total) = (8.235 mmol - 5.075 mmol) / (80.0 mL) = 0.395 M.

∵ pOH = -log[OH⁻]

∴ pOH = -log(0.395 M) = 1.4.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.4 = 12.6.

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