All categories

1 year ago

Calculate the volume in (L) of 1.13x10^5 grams of liquid sodium which has a density of 0.929g/cm3

Chemistry

1 answer:

Yuki888 [10]1 year ago

8 0

The volume of the liquid sodium is 121.64 L

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the above formula, we can obtain the volume of the liquid. Details below

<h3>How to determine the volume of the sodium liquid</h3>

Mass of liquid = 1.13×10⁵ g
Density of liquid = 0.929 g/cm³
Volume of liquid =?

Density = mass / volume

Thus,

Volume = mass / density

Volume of liquid = 1.13×10⁵ / 0.929

Volume of liquid = 121636.17 cm³

Divide by 1000 to express in liter

Volume of liquid = 121636.17 / 1000

Volume of liquid = 121.64 L

Learn more about density:

brainly.com/question/952755

#SPJ1

You might be interested in

A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure

Lesechka [4]

Answer:

the final volume of the gas is $V_2$ = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure $P_{ext}$ :

$P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}$

$P_{ext} = 1.03 \ atm$

The workdone W = $P_{ext}$ V

The change in volume ΔV= $\dfrac{W}{P_{ext}}$

ΔV = $\dfrac{130.1 \ J \times \dfrac{1 \ L \ atm}{ 101.325 \ J} }{1.03 \ atm }$

ΔV = $\dfrac{1.28398717 }{1.03 }$

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial volume = 61.5 mL

The change in volume V is $\Delta V = V_2 -V_1$

$- V_2= - \Delta V -V_1$

multiply through by (-), we have:

$V_2= \Delta V+V_1$

$V_2$ = 1250 mL + 61.5 mL

$V_2$ = 1311.5 mL

∴ the final volume of the gas is $V_2$ = 1311.5 mL

5 0

3 years ago

Complete the sentences about heme. Some terms will not be used. The prosthetic group of hemoglobin and myoglobin is . The organi

nevsk [136]

Explanation:

Haemoglobin consists of heme unit which is comprised of an $Fe^{2+}$ and porphyrin ring. The ring has four pyrrole molecules which are linked to the iron ion. In oxyhaemoglobin, the iron has coordinates with four nitrogen atoms and one to the F8 histidine residue and the sixth one to the oxygen. In deoxyhaemoglobin, the ion is displaced out of the ring by 0.4 Å.

The prosthetic group of hemoglobin and myoglobin is - Heme

The organic ring component of heme is - Porphyrin

Under normal conditions, the central atom of heme is - $Fe^{2+}$

In deoxyhemoglobin , the central iron atom is displaced 0.4 Å out of the plane of the porphyrin ring system.

The central atom has six bonds: four to nitrogen atoms in the porphyrin, one to a histidine residue, and one to oxygen.

7 0

3 years ago

Without constants you would not know which variable affected the

bonufazy [111]

Two independent variables could change at the same time, and you would not know which variable affected the dependent variable

4 0

3 years ago

Why is red the last color seen at sunset?

Dimas [21]

Within the visible range of light, red light waves are scattered the least by atmospheric gas molecules. So at sunrise and sunset, when the sunlight travels a long path through the atmosphere to reach our eyes, the blue light has been mostly removed, leaving mostly red and yellow light remaining.

8 0

4 years ago

What observations can you make about this group of people?

DedPeter [7]

Answer:The people are part of a softball team. They appear happy, they are showing number one with their fingers, and they are holding a trophy. They probably won the softball league championship

Explanation:

7 0

3 years ago