Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole
The mass of differences of reactant and product can be therefore
explained as
1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited
Hope this helps! 159.2086<span>Have a Good Day!</span>
Answer:
Increased use of resources
Additional waste produced
More construction
Cutting down trees
Sexually abstinent: refraining from some or all sexual activities
school (higher education)
health (stds)
pregnancy (not ready for children)
There's 6.022×10^23 particles in 1 mole of anything
like there is 1000 grams in 1 kilogram of anything