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vagabundo [1.1K]
3 years ago
10

A researcher claims that increasing temperature by 10 degrees will double the rate of an enzyme-catalyzed reaction. To test this

, he designed an experiment. For each tube, the researcher will measure the rate of product formation
Which best justifies the inclusion of tube 5 as a control?


It will provide a measurement of product formation in the absence of the substrate

It will provide a measurement of product formation in the presence of a denatured enzyme

It will show the effect of doubling the amount of substrate on the rate of product formation

It will show the effect of increased enzyme activity on the rate of product formation
Chemistry
1 answer:
BigorU [14]3 years ago
8 0

Answer:

It will provide a measurement of product formation in the presence of a denatured enzyme

Explanation:

For any experimental research study, it is a common practice to have sets of experimental runs as well as a control. The main essence of the control is to investigate the effects of a given substance such as an enzyme on the experimental conditions. This is done by comparing the experimental results in the presence of an enzyme with the results in the absence of an enzyme.

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3 years ago
In the citric acid cycle, after the acetyl-group (2C) from acetyl-CoA is transferred to oxaloacetate (4C) to produce citrate (6C
Alborosie

Answer:

The carbons of the acetyl group oxidize which generate CO2, and in turn H2O.

Explanation:

The pyruvic acid that is generated during glycolysis enters the mitochondria. Inside this organelle, the acid molecules undergo a process called oxidative decaborxylation in which an enzyme of several cofactors is involved, one of which is coenzyme A. Pyruvic acid is transformed into an acetyl molecule and these are been introduced to the begining of the Krebs Cycle where the acetyl-group (2C) from acetyl-CoA is transferred to oxaloacetate (4C) to produce citrate (6C). As the molecule cycles the two carbons of the acetyl oxidize and are released in the form of CO2. Then the energy of the Krebs cycle becomes sufficient to reduce three NAD +, which means that three NADH molecules are formed. Although a small portion of energy is used to generate ATP, most of it is used to reduce not only the NAD + but also the FAD which, if oxidized, passes to its reduced state, FADH2

8 0
3 years ago
Given the balanced equation representing a reaction: 2h2o(l) + 571.6 kJ -> 2h2(g) + o2(g). What occurred as a result of this
Ivan

Answer: option D) energy was absorbed and entropy increased.


Explanation:


1) Given balanced equation:


2H₂O (l) + 571.6 kJ → 2 H₂ (g) + O₂(g).


2) Being the energy placed on the side of the reactants means that the energy is used (consumed or absorbed). This is an endothermic reaction.


So, the first part is that energy was absorbed.


3) As for the entropy, it is a measure of the disorder or radomness of the system.


Since, two molecules of liquid water were transformed into three molecules of gas, i.e. more molecules and more kinetic energy, therefore the new state has a greater degree of radomness, is more disordered, and you conclude that the entropy increased.


With that, you have shown that the right option is D) energy was absorbed and increased.

7 0
4 years ago
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