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tamaranim1 [39]
3 years ago
13

Which of the following statements is/are correct? 1. There are 5 orbitals in

Chemistry
1 answer:
Naily [24]3 years ago
6 0
?? Como dices entonces hablas english
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What are the similarities and differences between light microscopes used by early scientists and light microscopes used today?
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Electron microscopes differ from light microscopes in that they produce an image of a specimen by using a beam of electrons rather than a beam of light. Electrons have much a shorter wavelength than visible light, and this allows electron microscopes to produce higher-resolution images than standard light microscopes
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3 years ago
Neon has 2 isotopes. Neon-20 has a mass of 19:992 amu and
Alenkinab [10]

Answer:

20.0928.

Explanation:

The average atomic mass is (90 * 19.992 + 10* 21) / 100

= 20.0928.

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3 years ago
Word Bank: Match each term with the sentence below
Ymorist [56]

Answer:

Electromagnetic Wave Medium Matter:The ability to move or change an object, or what a wave

Longitudinal Wave Trough Rarefaction: The area in a longitudinal wave where the particles are close together.

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3 years ago
Which is the least dense?
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1000 g of feathers is the least dense
6 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
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